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3 years ago

Simplify 2^x+4-2^x/5*2^x step by step

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

8 0

Answer:

4/ 5 x 2^x

Step-by-step explanation:

2^x +4-2^x / 5^2

First we multiply everything by 5^2/5^2

2^x + 4-2^x (5^2x) / (5^2)(5^2)

= 2^x + 4-2^x 5^2x we see 2 x 5^2

= 2^x+4-2 x 5^2x +5^2x / (5^2)(5^2x) 2^x cancels with 2^x as subtraction and 5^2x base cancels with top also

= 4/ 5 x 2^x

Furkat [3]3 years ago

7 0

That answer is to correct to support

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Answer:

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8 0

3 years ago

Below are the jersey numbers of 11 players randomly selected from a football team. Find the range, variance, and standard devia

jeyben [28]

Answer:

The range is 77.

The variance is 739.8.

The standard deviation is 27.2.

Step-by-step explanation:

The data provided, in ascending order is as follows:

S = {11 , 14 , 23 , 31 , 40 , 60 , 63 , 68 , 75 , 77 , 88}

The range of a data set is the difference between the maximum and minimum values.

From the above data set we know,

Maximum = 88

Minimum = 11

Compute the range as follows:

Range = Maximum - Minimum

= 88 - 11

= 77

The range is 77.

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum x_{i}=\frac{1}{11}\times [11+14+23+...+88]=50$

Compute the variance as follows:

$\sigma^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x})^{2}$

$=\frac{1}{11-1}\times [(11-50)^{2}+(14-50)^{2}+...+(88-50)^{2}]\\\\=\frac{1}{10}\times 7398\\\\=739.8$

The variance is 739.8.

Compute the standard deviation as follows:

$\sigma=\sqrt{\frac{1}{n-1}\sum (x_{i}-\bar x})^{2}}=\sqrt{739.8}=27.199265\approx 27.2$

The standard deviation is 27.2.

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3 years ago