The rate of change of the distance from the particle to the origin at this instant is 3 units per second.
<h3>What is the rate of change?</h3>
The instantaneous rate of change is the rate of change at a particular instant.
A particle is moving along the curve
The rate of change of y is given as:
dy / dx = 2
by differentiating both sides,
From the question, we have:
(x, y) = (5,24)
Substitute 5 for x and dy / dx = 2
Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.
Read more about rates of change at:
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An isometry is a transformation that preserves distance.
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Answer:
60.96437 is the 5 decimal place of 60.9643790503 number
Answer:
a) shown
b) h = [sqrt(17) - (5/2)t]²
c) t = 2sqrt(17)/5 seconds
Step-by-step explanation:
V = pi × r² × h
V = pi × 5² × h
V = 25pi × h
a) dV/dt = dV/dh × dh/dt
-5pi × sqrt(h) = 25pi × dh/dt
dh/dt = -sqrt(h)/5
b) 1/sqrt(h) .dh = -5. dt
2sqrt(h) = -5t + c
t = 0, h = 17
2sqrt(17) = 0 + c
c = 2sqrt(17)
2sqrt(h) = -5t + 2sqrt(17)
sqrt(h) = [2sqrt(17) - 5t] ÷ 2
sqrt(h) = sqrt(17) - (5/2)t
Square both sides
h = [sqrt(17) - (5/2)t]²
c) empty: h = 0
0 = [sqrt(17) - (5/2)t]²
sqrt(17) - (5/2)t = 0
(5/2)t = sqrt(17)
t = 2sqrt(17)/5
t = 1.64924225 seconds
sqrt: square root
Angle 3, 6, and 8 have the same measure as angle 1
