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2 years ago

6

The total length of a beach is 14.4 kilometers. If lifeguards are stationed every 0.06 kilometers, including one at the end of t

he beach, how many lifeguards will there be on the beach?

1 answer:

belka [17]2 years ago

5 0

Answer:

240

Step-by-step explanation:

Divide 14.4 by 0.06, as the total distance is 14.4 kilometers and lifeguards are stationed every 0.06 kilometers.

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Which expression is equivalent to 4(x^3)(2x)^-4

AVprozaik [17]

Answer:

= $\frac{4x^{3}}{16 x^{4}}$

Step-by-step explanation:

$4(x^{3} )(2x)^{-4}$

= $\frac{4x^{3}}{(2x)^{4}}$

= $\frac{4x^{3}}{2^{4} x^{4}}$

= $\frac{4x^{3}}{16 x^{4}}$

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3 years ago

Find the distance and midpoints of the following points:

timofeeve [1]

1.) (2, 4) and (10, 8)
Distance: 4√5
Midpoint: (6, 6)

2.) (3, 8) and (7, 3)
Distance: √41
Midpoint: (5, 11/2)

3.) (4, 9) and (9, 5)
Distance: √41
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3 years ago

The difference of the range and the interquartile range of the data set represented by the box plot is .

Ivahew [28]

When presented with a box plot, it is better to identify the 5 numbers that are important in the box plot.

5 number summary of the boxplot.
1) minimum number - 16
2) 1st quartile - 21
3) 2nd quartile or median - 26
4) 3rd quartile - 29
5) maximum number - 34

Range is the difference of the maximum value from the minimum value of the data set.
Interquartile range is the difference of the 3rd quartile from the 1st quartile.

Range: 34 - 16 = 18
IQR: 29 - 21 = 7

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3 years ago

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A number is greater than 8 The same number of possible solutions to the inequality

Gre4nikov [31]

Answer:

48

Step-by-step explanation:

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2 years ago

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The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of a bridge is 1270 ft long and

deff fn [24]

Answer:

Step-by-step explanation:

Given

span of bridge $L=1270\ ft$

height of span $h=157\ ft$

Equation of Parabola

$y=0.00039x^2$

$|x|$ i.e.

$-635$

$\frac{dy}{dx}=2\times 0.00039$

length of Arc $=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}$

$=\int_{-635}^{635}\sqrt{1+(\frac{dy}{dx})^2}$

$=\int_{-635}^{635}\sqrt{1+(0.00078x)^2}$

$=2\times \int_{0}^{635}\sqrt{1+(0.00078x)^2}$

$=2\times (660.08)$

$=1320.16\ ft$

4 0

2 years ago