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Klio2033 [76]
2 years ago
6

The total length of a beach is 14.4 kilometers. If lifeguards are stationed every 0.06 kilometers, including one at the end of t

he beach, how many lifeguards will there be on the beach?
Mathematics
1 answer:
belka [17]2 years ago
5 0

Answer:

240

Step-by-step explanation:

Divide 14.4 by 0.06, as the total distance is 14.4 kilometers and lifeguards are stationed every 0.06 kilometers.

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A. (0, -2)
Anastaziya [24]

Answer: D

Step-by-step explanation: edge

3 0
3 years ago
Solve each equation 6=1-2n+5
kirill115 [55]
2n+5=6+1
2n=7-5
n=2/2
N=1
4 0
3 years ago
Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 9 − x2 − y2 and the
Katyanochek1 [597]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
4 0
3 years ago
Is the function even odd or neither?
Mandarinka [93]

The answer is the first option: Even.

The explanation for this exercise is shown below:

1. By definition, if f(x)=f(-x) the fucntion is even.

2. When the graph is symmetric with respect to the y-axis, it is an even function.

3. As you you can see in the graph attached in the problem, the graph is symmetric about the y-axis. Therefore, you can conclude it is an even function.

5 0
3 years ago
I NEED HELP ASAP!!<br><br> Subtract.<br><br> -30-27= ?<br><br> -5-(-4)= ?
pashok25 [27]
-30-27= -57
When both numbers are negative, they are “added” in a sense, but remain negative.

-5-(-4)= -1
You have to multiply the (-4) by the “invisible” -1 on the outside before you add/subtract.
5 0
3 years ago
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