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S_A_V [24]
3 years ago
8

Jason needs to save at least $200 by the end of the summer. He already has $40, and he has 8 weeks to save. Which inequality can

he use to decide how much he needs to save each week?
Mathematics
2 answers:
yan [13]3 years ago
5 0

Answer:

  • 8x + 40 ≥ 200
  • At least $20 each week

Step-by-step explanation:

  • Target amount = at least $200
  • Jason already has = $40
  • Time = 8 weeks
  • Saved amount each week = x

<u>Required inequality:</u>

  • 8x + 40 ≥ 200
  • 8x ≥ 160
  • x ≥ 160/8
  • x ≥ $20

Veseljchak [2.6K]3 years ago
3 0

Step-by-step explanation:

y=mx+b

200 = 8x + 40

Rearrange,

x = 160/8 = 20

He would need to save $20 a week

200= 20 × 8 + 40

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Bryce grows a sunflower that contains 1,354 sunflower seeds. Six people share the harvested seeds. If they share the seeds equal
iragen [17]

Answer: 4 seeds will left over.

Step-by-step explanation:

Total sunflower seeds = 1354

Number of people shared sunflower  seeds equally = 6

By division operation,

Number of seeds each people will get = (Total sunflower  seeds) ÷ (Number of people shared seeds equally)

= (1354) \div (6)

=225\dfrac{4}{6}

Hence, each people will get 256 sunflower seeds and 4 seeds will left.

5 0
3 years ago
Paws at play made a total of $1234 grooming 22 dogs. Paws at Play charges $43 to groom each small dog and $75 for each large dog
vitfil [10]

Answer:

<u>Answer (a):</u>

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

<u>Answer (b)</u>

9 large dogs.

Step-by-step explanation:

Paws at Play made a total of $1234 grooming 22 dogs.

Paws at Play charges $43 to groom each small dog and;

$75 for each large dog.

Let the number of small dogs be 's'

And the number of large dogs be 'l'

<u>A system of equations will be:</u>

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;

43s + 43l = 946 ... (i)

43s + 75l = 1234 ... (ii)

Subtracting (i) from (ii) we get;

32l = 288 , l = \frac{288}{32} = 9

So there are 9 large dogs.

8 0
3 years ago
Which expression is equivalent to
bazaltina [42]

Answer:

<h2><em><u>c</u></em></h2>

Step-by-step explanation:

6m+9q-3mq+4m= 10m + 9q - 3mq = C

7 0
3 years ago
Read 2 more answers
A television game show has 11 ​doors, of which the contestant must pick 3. Behind 3 of the doors are expensive​ cars, and behind
bezimeni [28]

For there to be 1 car, we consider two possible outcomes:

The first door opened has a car or the second door opened has a car.

P(1 car) = 2/6 x 4/5 + 4/6 x 2/5

P(1 car) = 8/15

For there to be no car in either door

P(no car) = 4/6 x 3/5

P(no car) = 2/5

Probability of at least one car is the sum of the probability of one car and probability of two cars:

P(2 cars) = 2/6 x 1/5

= 1/15

P(1 car) + P(2 cars) = 8/15 + 1/15

= 3/5

6 0
3 years ago
Which is true about the polynomial –8m3 + 11m?
Dima020 [189]

Answer:

Binomial with a degree of 3

Step-by-step explanation:

-8m^3 + 11m....notice that it has 2 terms....(-8m^3) and (11m). Having 2 terms makes it a binomial...if it would have had 3 terms, it would have been a trinomial. If it has only one variable, the degree is the highest exponent...so this has a degree of 3 since ^3 is the highest exponent.

so the answer is : binomial with a degree of 3

7 0
3 years ago
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