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3 years ago

First to answer correctly gets brainliest

Mathematics

2 answers:

FinnZ [79.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

Gala2k [10]3 years ago

5 0

Answer:

It's C -3,2 and 5 only

Step-by-step explanation:

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Find the remainder when f(x) = x3 − 14x2 + 7x − 10 is divided by x − 3. 184 164 −88 −122

Fudgin [204]

Answer:

122

Step-by-step explanation:

For this case we must build a quotient that, when multiplied by the divisor, eliminates the terms of the divide until it reaches the remainder.

It must be fulfilled that:

Dividend = Quotient * Divisor + Remainder

we have that the remainder is 122.

have a good day

5 0

3 years ago

If x= 27 and y= 54 then what does w equal

beks73 [17]

The answer is 81 because 27 x 3

4 0

3 years ago

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A sport man runs 96m in 8seconds. Find the rate in metres per seconds

mina [271]

Answer:

12m/s

Step-by-step explanation:

96/8 = 12

5 0

3 years ago

The function value.

Zepler [3.9K]

f(7)

f(x) = 5x

replace x with 7

f(7) = 5(7) = 35

the answer is 35

3 0

3 years ago

Read 2 more answers

Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . <em>The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.</em>

3 0

3 years ago