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kotegsom [21]
3 years ago
15

write a function that returns a list, where each member of list contains previous day’s value multiplied by 2.​

Computers and Technology
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

Explanation:

The following code is written in Java, the function takes in a list with the previous day's values. The function then uses that list, loops through it and multiplies each individual value by 2 and returns the modified list. The first red  square represents the test case for the function, while the second red square in the image represents the output.

 public static ArrayList<Integer> doubleIt(ArrayList<Integer> mylist) {

       for (int x = 0; x<mylist.size(); x++) {

           mylist.set(x, mylist.get(x)*2);

       }

       return mylist;

   }

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Define a function compute_gas_volume that returns the volume of a gas given parameters pressure, temperature, and moles. Use
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Question:

Define a function compute_gas_volume that returns the volume of a gas given parameters pressure, temperature, and moles. Use the gas equation PV = nRT, where P is pressure in Pascals, V is volume in cubic meters, n is number of moles, R is the gas constant 8.3144621 ( J / (mol*K)), and T is temperature in Kelvin.

Answer:

This solution is implemented in C++

double compute_gas_volume(double P, double T, double n){

   double V = 8.3144621 * n * T/P;

   return V;

}

Explanation:

This line defines the function, along with three parameters

double compute_gas_volume(double P, double T, double n){

This calculates the volume

   double V = 8.3144621 * n * T/P;

This returns the calculated volume

   return V;

}

To call the function  from the main, use:

<em>cout<<compute_gas_volume(P,T,n);</em>

<em />

<em>Where P, T and n are double variables and they must have been initialized</em>

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