See attachment although I gather this is not your question. I did the graph(s) for the function,
Vas happenin!
Hope your day is going well
I think it’s A
Sorry if it’s wrong
Hope this helps *smiles*
Answer:
Step-by-step explanation:
From the given data
we observed that the missile testing program
Y1 and Y2 are variable, they are also independent
We are aware that
have
distribution with 1 degree of freedom
and
has x^2 with 2 degree of freedom

Since we have to find the density formula

We use method of transformation

There inverse function is 
We derivate the fuction above with respect to u

Therefore,

5 cm = 2km
Scale= 5 cm : 200000 cm
= 1 : 40000
a. 1 : 40000 = x : 500000
x = 12.5 cm
b.1 : 40000 = 2 : x
x = 80000 cm
x = 0.8 km
Answer:
your answer is correct.
Step-by-step explanation:
For the purpose here, we'll call the missing point on the arc through Z point X.
Essentially, you want to make ΔXYZ ≅ ΔLMN by SSS. The construction so far ensures LM ≅ MN ≅ XY ≅ YZ. By copying the length LN to XZ, you ensure the congruence of the remaining sides of the triangles.
Then ∠XYZ ≅ ∠LMN because corresponding parts of congruent triangles are congruent.
In short, XZ needs to be the same distance as LN.