Answer:
see explanation
Step-by-step explanation:
Calculate C by adding corresponding components of A + B
C =
+ ![\left[\begin{array}{ccc}-2.5\\5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2.5%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4-2.5\\-7.5+5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-2.5%5C%5C-7.5%2B5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1.5\\-2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1.5%5C%5C-2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Answer:
A sample size of 183 is needed.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 2.17.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
Margin of error within 0.023 ppm of mercury with 97% confidence. What sample size is needed?
We have to find n for which
. We have that
. So






We have to round up(182 is not quite in the desired margin of error), so a sample size of 183 is needed.