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alexira [117]
3 years ago
7

A granular substance such as sand naturally settles into a cone-shaped pile when poured from a small aperture. Its height depend

s on the humidity and adhesion between granules. The angle of elevation of a pile, θ, is called the angle of repose. If the height of a pile of sand is 15 feet and its diameter is approximately 52 feet, determine the angle of repose. Round answer to nearest degree.
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

The angle of elevation of the pile is 30°

Step-by-step explanation:

Given that;

Height = 15 ft

Diameter = 52 ft

so radius r = D/2 = 52/2 = 26 ft

Now, to get the angle of elevation.

given the details in the question,

we can say; the given height is the opposite which is 15 ft.

Also the radius is adjacent which is 26 ft

using SOH CAH TOA

TOA; Tan = Opposite / Adjacent

so

tan∅ = 15 ft / 26 ft

tan∅ = 0.5769

∅ = tan⁻¹( 0.5769 )

∅ = 29.98° ≈ 30°

Therefore, The angle of elevation of the pile is 30°

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3 years ago
Please help how do I do this
Dmitriy789 [7]

Answer:

a = 2.5
b = 4.33

Step-by-step explanation:

a = sin(30 degrees) = o/5 = 2.5
b = cos(30 degrees) = a/5 = (5root3) / 2 or about 4.33

verify using Pythagorean theorem
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7 0
2 years ago
A square is inscribed in a circle such that each corner touches the circle.
Scrat [10]

Answer:

A(r) = √2 * r

A(r) Domain is   R { r ;  r > 0}

Step-by-step explanation:

Diagonals of a square intercept each other in a 90° angle. The four triangles resulting from diagonal interception are equal and are isosceles triangles, with hipotenuse a side of the square

Therefore we apply  Pythagoras theorem

Let   x be side of square, and r radius of the circle, ( diagonals touch the circle) then

x²  =  r² + r²

x²  = 2r²

x   =  √2 * r

Now Aea of square is :

A  =  L²          where L is square side

A(r)  = √2 * r

Domain of A(r)    =   R { r, r > 0}

6 0
3 years ago
Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b
pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2, \sigma = 0.33

What is the minimum level for which the battery pack will be classified as highly sought-after class

At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 2}{0.33}

X - 2 = 0.33*1.28

X = 2.42

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

4 0
3 years ago
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