Answer:
The answer is B:8
Step-by-step explanation:
because when you line up the numbers in order
5 6 7 8 11 11 15
The middle number is 8
Count the number of multiples of 3, 4, and 12 in the range 1-2005:
⌊2005/3⌋ ≈ ⌊668.333⌋ = 668
⌊2005/4⌋ = ⌊501.25⌋ = 501
⌊2005/12⌋ ≈ ⌊167.083⌋ = 167
(⌊<em>x</em>⌋ means the "floor" of <em>x</em>, i.e. the largest integer smaller than <em>x</em>, so ⌊<em>a</em>/<em>b</em>⌋ is what you get when you divide <em>a</em> by <em>b</em> and ignore the remainder)
Then using the inclusion/exclusion principle, there are
668 + 501 - 2•167 = 835
numbers that are multiples of 3 or 4 but not 12. We subtract the number multiples of 12 twice because the sets of multiples of 3 and 4 both contain multiples of 12. Subtracting once removes the multiples of 3 <em>and</em> 4 that occur twice. Subtracting again removes them altogether.
What you need to do here is a vector addition of the ship's velocity with respect to the water (V1), plus the velocity of the water with respect to land (V2).
Also remember that:
<span>i = unit vector east </span>
<span>j = unit vector north </span>
<span>V1 = 30 sin 192 i + 30 cos 192 j </span>
<span>V2 = 14 sin 112 i + 14 cos 112 j. </span>
The formula will look like this
<span>V1 + V2 = ?
Now please use the data to put the values into correct places and there you go! Hope this helps</span>
Six pounds of rice is $18 homie
