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EleoNora [17]
3 years ago
12

A group of adults plus one child attend a movie at Regal Cinemark. Tickets cost $11 for adults and $7 for children. The total co

st for the movie is $72. Write an equation to find the number of adults in the group.
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

Y=11x+7

Step-by-step explanation:

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Find the 75th term of the following6, 10, 14, 18,
enot [183]

Given the sequence:

6, 10, 14, 18,...

We will find the 75th term

The given sequence is an arithmetic sequence

Because there is a constant common differnce

d = 18 - 14 = 14 - 10 = 10 - 6 = 4

The first term = a = 6

The general formula of the arithmetic sequence is as follows:

a_n=a+d(n-1)

Where: n is the nth term

To find the 75th term, substitute with n = 75 and a = 6, d = 4

a_{75}=6+4\cdot(75-1)=302

So, the answer will be the 75th term = 302

7 0
1 year ago
What is the exponent of x in in the expression -4x^3y^2 + 6
liberstina [14]

Answer:

3

Step-by-step explanation:

- 4x³y² + 6

the x is raised to the power of 3 , that is exponent of x is 3

4 0
2 years ago
The perimeter of a picture frame is 24 inches. If the width of the picture frame is 5 inches, what is the length of the picture
Zarrin [17]
L=7
2l+2w=24
2l+2x5=24
2l+10=24
2l=14
l=7
3 0
3 years ago
Read 2 more answers
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

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