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julsineya [31]
3 years ago
15

Abel is making brownies for a bake sale.

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

You did not post an image.

Step-by-step explanation:

You might be interested in
Which number should come next in the series?<br> 1 - 1 - 2 - 3 - 5 - 8 - 13
Darya [45]
This is part of the Fibonacci sequence. The next number is 21. Look at how much each number increases and the number before it.

1+1=2 (the number after 1 and 1)
1+2=3 (the number after 1 and 2)
2+3=5 (the number after 2 and 3)

So to solve we add 13+8=21
8 0
3 years ago
Which quadratic equation fits the data in the table? x -5,-2,-1,0,3,4,6 y 33,9,5,3,9,15,33
mojhsa [17]

Answer:

y = x² − x + 3

Step-by-step explanation:

Quadratic equation is:

y = ax² + bx + c

Pick three points and plug in.  I'll choose (-2, 9), (-1, 5), and (0, 3).

9 = a(-2)² + b(-2) + c

5 = a(-1)² + b(-1) + c

3 = a(0)² + b(0) + c

9 = 4a − 2b + c

5 = a − b + c

3 = c

We know c = 3, so substitute into the first two equations:

9 = 4a − 2b + 3

5 = a − b + 3

0 = 4a − 2b − 6

0 = a − b − 2

Solve by elimination or substitution.

b = a − 2

0 = 4a − 2(a − 2) − 6

0 = 4a − 2a + 4 − 6

0 = 2a − 2

a = 1

b = -1

Therefore:

y = x² − x + 3

6 0
3 years ago
In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o
ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = \frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}

X = 0.13

s = \sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for t_{6,0.005} is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = t_{6,0.005} . \frac{s}{\sqrt{N} }

E = 3.707. \frac{0.029}{\sqrt{7} }

E = 0.041

The interval will be:  

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0
3 years ago
If u guys answer this one ill give away free p​
yawa3891 [41]

Answer:

\frac{50}{7}

Step-by-step explanation:

Swap the fraction,

5 *\frac{10}{7} = \frac{50}{7}

or around 7.142...

3 0
3 years ago
50,000 in scientific notation would be _____. 5 × 10^5 0.05 × 10^6 5 5 × 10^4 50,000
vovangra [49]

Answer:

Just count the number of zeros:

Step-by-step explanation:

There are 4 zeros, so the answer is 5 x 10^4.

6 0
3 years ago
Read 2 more answers
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