Answer:
h+c=28
4h+2c=80
Step-by-step explanation:
The total amount of horses and chickens is 28. So h+c=28. Each horse has 4 legs. Each chicken has 2 legs. There are h amount of horses and c amount of chickens. So 4h+2c=80.
h+c=28
4h+2c=80
Firstly, solve 38C15.
Then solve 42C12.
Compare your answers.
The goal here is to see if 38C15 = 42C12.
Here is the formula:
nCr = n!/(r!(n - r)!
Go for it.
Answer:
32
Step-by-step explanation:
x+102=4x+6
102=3x+6
96=3x
32=x
Hope this helps!!!
Answer:
Mark me as brainlist
Step-by-step explanation:
Use logarithms to solve exponential equations whose terms cannot be rewritten with the same base
Solve exponential equations of the form
y
=
A
e
k
t
for t
Recognize when there may be extraneous solutions or no solutions for exponential equations
So what we have to do to solve this problem is to write down those values in 2 equations (one that represents what you sold and the other what your friend sold) compare them and find how much each ticket is worth.
First equation : 11x + 8y = 158
Where x = how much each adult ticket is
and y = how much each student ticket is
The second equation is : 5x + 17y = 152
Using the method of substitution , we can compare each equation side by side:
11x + 8y = 158
5x + 17y = 152
Now we need to set one of the variables of both equations so they are equal:
11(5)x + 8(5) = 158(5)
5(11)x + 17(11)x = 152(11)
55x + 40y = 790
55x + 187y = 1672
Then we subtract the second equation by the first one
55x-55x + 187y - 40y = 1672 - 790
147y = 882
y = 6
The we apply y to one of the equations to discover x :
11x + 8y = 158
11x + 8(6) = 158
11x + 48 = 158
11x = 110
x = 10
So the awnser is :
Each adult ticket (x) is $10
And each student ticket (y) is $8
I hope you understood my explanation,
