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Leokris [45]
3 years ago
8

What value of x is in the solution set of 8x - 6 > 12 + 2x? O-1 O0 O3 O5

Mathematics
1 answer:
otez555 [7]3 years ago
4 0

The answer of X will be equal (3)

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Write an equation to represent the sequence<br> 19, 38, 57, 76,95 ...
morpeh [17]

Answer:

Step-by-step explanation:

lets look at the numbers

38-19=19

57-38=19

76-57=19

aₙ=aₙ-₁ +19

8 0
3 years ago
Solve |x+ 3|- 1 = (x + 2)^2 by graphing.<br> The solutions are x =<br> and x =
Setler [38]

9514 1404 393

Answer:

  x = -2, x = -1

Step-by-step explanation:

A graphing calculator solves this nicely, as shown in the attachment.

  x = -2, x = -1

__

The given equation resolves to two equations.

<u>x+3 < 0</u>

  -(x +3) -1 = (x +2)^2

  x^2 +5x +7 = 0

Checking the discriminant, we find ...

  b^2 -4ac = (5)^2 -4(1)(7) = 25 -28 = -3

There are only complex solutions to this equation.

__

<u>x+3 ≥ 0</u>

  x +3 -1 = (x +2)^2

  (x +2)^2 -(x +2) = 0 . . . .subtract x+2

  (x +2)(x +2 -1) = 0 . . . . . factor

Solutions are values of x that make these factors zero.

  x +2 = 0   ⇒   x = -2

  x +1 = 0   ⇒   x = -1

<em>Domain Check</em>

  x +3 = -2 +3 = 1 > 0 . . . . as required.

5 0
3 years ago
Which best describes the relationship between the successive terms in the sequence shown?
OverLord2011 [107]

Answer:

the common difference is 10

7 0
3 years ago
Read 2 more answers
The average length of a field goal in the National Football League is 38.4 yards, and the s. d. is 5.4 yards. Suppose a typical
Tasya [4]

Answer:

a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b) 0.25% probability that his average kicks is less than 36 yards

c) 0.11% probability that his average kicks is more than 41 yards

d-a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

d-b) 1.32% probability that his average kicks is less than 36 yards

d-c) 0.80% probability that his average kicks is more than 41 yards

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 38.4, \sigma = 5.4, n = 40, s = \frac{5.4}{\sqrt{40}} = 0.8538

a. What is the distribution of the sample mean? Why?

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b. What is the probability that his average kicks is less than 36 yards?

This is the pvalue of Z when X = 36. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{0.8538}

Z = -2.81

Z = -2.81 has a pvalue of 0.0025

0.25% probability that his average kicks is less than 36 yards

c. What is the probability that his average kicks is more than 41 yards?

This is 1 subtracted by the pvalue of Z when X = 41. So

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{0.8538}

Z = 3.05

Z = 3.05 has a pvalue of 0.9989

1 - 0.9989 = 0.0011

0.11% probability that his average kicks is more than 41 yards

d. If the sample size is 25 in the above problem, what will be your answer to part (a) , (b)and (c)?

Now n = 25, s = \frac{5.4}{\sqrt{25}} = 1.08

So

a)

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

b)

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{1.08}

Z = -2.22

Z = -2.22 has a pvalue of 0.0132

1.32% probability that his average kicks is less than 36 yards

c)

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{1.08}

Z = 2.41

Z = 2.41 has a pvalue of 0.9920

1 - 0.9920 = 0.0080

0.80% probability that his average kicks is more than 41 yards

4 0
3 years ago
A cherry falls from a tree branch that is 9 feet above the ground.
miss Akunina [59]
The cinematic equation is:
 h (t) = (1/2) * a * t ^ 2 + vo * t + h0
 Where,
 a: acceleration
 vo: initial speed
 h0: initial height
 Substituting values:
 h (t) = (1/2) * (- 32) * t ^ 2 + (0) * t + 9
 h (t) = - 16t ^ 2 + 9
 For t = 0.2 we have:
 h (0.2) = - 16 * (0.2) ^ 2 + 9
 h (0.2) = 8.36 feet
 To touch the ground we have:
 -16t ^ 2 + 9 = 0
 16t ^ 2 = 9
 t = root (9/16)
 t = 0.75 s
 Answer:
 
The height of the cherry after 0.2 seconds is:
 
h (0.2) = 8.36 feet
 
the cherry hits the ground at:
 
t = 0.75 s
5 0
3 years ago
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