Group and factor
group y's with y's and z's with z's
(y²-10y)+(10z-yz)
factor
y(y-10)+z(10-y)
force undistribute -1
-y(10-y)+z(10-y)
factor
(10-y)(-y+z)
(z-y)(10-y) or
(y-z)(y-10)
Answer:
PQ = 20
Step-by-step explanation:
Theorem: The length of the median of a trapezoid is the average of the base lengths.

PQ + 12 = 32
PQ = 20
See how easy that is if you know the theorem!
P = A/D, Where P = Monthly payments, A = Total amount owed = 15,000-1,500 = $13,500,

r = 5% = 0.05, nt = 12*3 = 36
Therefore,
D =

= 33.37
Then,
P = 13,500/44.37 = $404.61
The correct answer is c.
Answer: I believe this will be your answer for this.
<u>x = </u>
<u> so basically this is your solution of x equaling to 2 over 729.</u>
<u>(hope this helps!)</u>
A small company plans to invest in a new advertising campaign.
There is a 20% chance that the company will lose $5,000 ,
50% chance of a break even, and a 30% chance of a $10,000 profit
So the expected value from the advertisement campaign is calculated as - 20% of 5000 + 0% of 5000 + 30% of 10,000
= -1000 + 0 + 3000
= 2000
The expected value from the advertisement campaign is $2000.
So the Company must go ahead with the campaign.
Answer : Option A
Hope it helps.
Thank you ..!!