Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
Step-by-step explanation:
√(-100)
Use the imaginary number rule 
√(-1) × √(100)
i × √(10²)
i × 10
= 10i
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We are given equation: c=6.4w, where the cost c for w pounds of walnuts.
w represents the number of pounds of walnuts.
Number of pounds could be in decimals.
The value of w = 2.5 represents 2.5 pounds of walnuts.
On plugging w=2.5 in c=6.4w equation, we get.
c=6.4×2.5 = $16.
Therefore, for 2.5 pounds of walnuts the total cost is $16.
Hence, <u>a value of 2.5 for w make sense in this situation. It shows that cost of 2.5 pounds of walnuts is $16, where cost of each pound of walnuts is 6.4.</u>
