Determine equation for line that is perpendicular to x=-2 and passes through the point (6,1)
1 answer:
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Answer:
second option
Step-by-step explanation:
Given
+ 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± = ± i ( noting that
= i ), and
x² = - 5 ( take the square root of both sides )
x = ± = ±
= ±
×
= ± i
Solutions are x = ± i and x = ± i
<u>Answer:</u>
The variable that has the highest power is considered to be the degree of polynomials in an algebraic equation.
A column:
1) .
The degree is 3.
2).
The degree is 2.
3)
The degree is 1.
B column:
1)
The degree is 2.
2)
The degree is 2.
3)
The degree is 3.
A×B columns:
While Multiplying two terms in a equation, if the variables are same then multiply the constant value and sum the exponent value.
1) .
=
The degree is 5.
2) .
=.
The degree is 4.
3) .
The degree is 4.
