The equation of a line is y=-1/4x-7, (option 1)
<h3>
What is the equation of a line? </h3>
A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis.
<h3>
How do you find the equation of a line?</h3>
Write the equation in the form y = mx + b to find the slope m and the y-intercept. This will allow you to graph the equation using the slope and y-intercept.
Given:-
Equation of the line is y=4x+8
The point through which the line passes (-8,4).
here the slope of the line is m1=4
To find the perpendicular line we know the formula
m1*m2=-1
By putting the value of m1 we get m2= -1/4
By using the one-point formula of the line we have
=>(y-y1)=m2*(x-x1)
By putting the values of y1 and x1 we get
(y1,x1)=(-8,4)
=>(y+8)=-0.25*(x-4)
y+0.25x+7=0
Hence the desired equation of the line is y=-1/4x-7
To find more about the straight line equations visit :
brainly.com/question/25969846
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Answer is 5<span>√2 (second choice)
c^2 = 5^2 + 5^2
c^2 = 50
c = </span><span>√50
c = </span>√25 <span>√2
c = 5</span><span>√2</span>
