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3 years ago

a triangle has two sides of lengths 5 and 12, what value could the length of the third side be? check all that apply

Mathematics

1 answer:

Goshia [24]3 years ago

5 0

Answer:

11 and 9

Step-by-step explanation:

The inequality is 12-5<x<12+5, which simplifies to 7<x<17, so the length of the third side can be any number between 7 and 17, but not including those numbers.

The answer is 11 and 9

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2/3 - 5bx = bx + 1/3 In the equation shown above, b is a constant. For what value of b = NO SOLUTIONS? A. 5 B. 0 C. -5 D. 2/5

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

Here, we want to know at what values of b does the equation becomes not solvable

Now looking at the left hand side, we have;

2/(3-5bx) and also the right hand side bx + 1/3

For this expression if we insert b = 0, then automatically x cancels out on both sides of the equation and we shall be left with nothing to solve

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3 years ago

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Leviafan [203]

The answer would be D

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3 years ago

Read 2 more answers

Bob and Chris share money in the ratio 2:3 Bob receives £8 Work out how much Chris receives

sweet-ann [11.9K]

Step-by-step explanation:

total ratio is 5

first find the total amount

bob's ratio is 2/5

so 2/5 ×total amount=8 pounds

0.4 ×total amount=8 pounds

total amount=8/0.4=20 pounds

so chris receives: 20-8=12 pounds

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20k%20-%20%28k%20%2B%20%20%5Cfrac%7B1%7D%7B4%7D%29%20%3D%20%20%5Cfrac

VikaD [51]

Firstly, foil -(k + 1/4) (think of the minus sign as -1):

$\frac{2}{3}k-k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Next, combine like terms:

$-\frac{1}{3}k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Next, we have to add 1/3k on both sides, but first we have to find the LCD, or lowest common denominator, of 3 and 12. To do this, list the multiples of both and the lowest one they share is their LCD. In this case, the LCD is 12. Multiply both sides of -1/3 by 4/4 and 1/12 by 1/1:

$-\frac{1}{3}\times \frac{4}{4}=-\frac{4}{12}\\\\\frac{1}{12}\times \frac{1}{1}=\frac{1}{12}\\\\-\frac{4}{12}k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Now add 4/12k on both sides of the equation:

$-\frac{1}{4}=\frac{5}{12}k+\frac{4}{12}$

Next, to subtract 4/12 on both sides we need to find the LCD of 4 and 12. It's the similar process as we did with 12 and 3. This time the LCD is also 12. Multiply both sides of -1/4 by 3/3 and 4/12 by 1/1:

$-\frac{1}{4}\times \frac{3}{3}=-\frac{3}{12}\\\\\frac{4}{12}\times \frac{1}{1}=\frac{4}{12}\\\\-\frac{3}{12}=\frac{5}{12}k+\frac{4}{12}$