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Virty [35]
3 years ago
13

Hannah has 19 more bouncy balls than Stefan. Stefan has b bouncy balls. Write an expression that shows how many bouncy balls Han

nah has.
Mathematics
2 answers:
zhenek [66]3 years ago
8 0

Answer:19+ b

Step-by-step explanation:

meriva3 years ago
3 0

Answer:

B + 19

Step-by-step explanation:

B is an unknown number. *

-

Example.

If Stefan has 1 bouncy ball, Hannah would have 20.

Formula.

Stephan's Amount + 19 = Hannah's Amount

Solving Your Problem.

We will do the same thing except replacing "1" with "b".

b = Stefan's Amount

b + 19 = Hannah's Amount

We are just adding 19 to his.

-

Note: In Algebra, we use lowercase variables usually...just a side note.

-

I hope I helped you solving this problem, and sorry if I have bad english. I am learning every day thank you! :)

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Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0
3 years ago
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