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anzhelika [568]
3 years ago
13

Find the 1st term of a sequence if the common difference = -2 and the 13th term =59

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

83

Step-by-step explanation:

<u>Formula for 13th term:</u>

t(13) = a + 12d, where a- first term, d- common difference

<u>Given</u>

  • t(13) = 59
  • d = -2
  • a = ?

<u>As per the formula for 13th term:</u>

  • 59 = a + 12*(-2)
  • 59 = a - 24
  • a = 59 + 24
  • a = 83
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Answer:

D. 0.9938.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

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In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 115 and a standard deviation of 8.

This means that \mu = 115, \sigma = 8

100 people are randomly selected

This means that n = 100, s = \frac{8}{\sqrt{100}} = 0.8

Find the probability that their mean blood pressure will be less than 117.

This is the p-value of Z when X = 117, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{117 - 115}{0.8}

Z = 2.5

Z = 2.5 has a p-value of 0.9938, and thus, the correct answer is given by option D.

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