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tatiyna
3 years ago
15

0.002191 in scientific notation

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
8 0
0.002191 in scientific notation
2.191 × 10-3
miskamm [114]3 years ago
5 0

Answer:

2.191 · 10^{-3}

Step-by-step explanation:

0.002191

2.191 · 10^{-3}

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In establishing warranties on HDTV sets, the manufacturer wants to set the limits so that few will need repair at the manufactur
Novosadov [1.4K]

Answer:

If the warranty limits are at 41.12 months, only 10 percent of the HDTVs need repairs at the manufacturer's expense.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

For a new HDTV the mean number of months until repairs are needed is 36.84 with a standard deviation of 3.34 months. This means that \mu = 36.84, \sigma = 3.34.

Where should the warranty limits be set so that only 10 percent of the HDTVs need repairs at the manufacturer's expense?

This is the value of X when Z has a pvalue of 0.90.

Looking at the z-table, we get that this is between Z = 1.28 and Z = 1.29, so we use Z = 1.285.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 36.84}{3.34}

X - 36.84 = 1.28*3.34

X = 41.12

If the warranty limits are at 41.12 months, only 10 percent of the HDTVs need repairs at the manufacturer's expense.

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Answer:

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Step-by-step explanation:

2x-7(y+1)

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