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3 years ago

Change 2.56 into a percentage * 0.0256% 25.6% 256.0% none of the above

Mathematics

2 answers:

Ksivusya [100]3 years ago

8 0

Answer:

C: 256%

Step-by-step explanation:

True [87]3 years ago

4 0

256%! Just multiply by 100, or shift decimal 2 places right:)

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Charlotte has two job offers as a car sales person. The first job will pay her $600 a month plus 2% on the price of her car sale

Lana71 [14]

$40,000
Let x be the sales amount.
600+0.02x=1000+0.01x
x=$40,000

5 0

3 years ago

(7w+4h)+ 5(2w+3h)- 2(w+h)

jasenka [17]

7w + 4h + 10w + 15h - 2w - 2h
= 15w + 17h

3 0

3 years ago

Read 2 more answers

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

4 0

3 years ago

6k+4k<-4k+6 solve for k

Genrish500 [490]

Answer:

k < 3/7

Step-by-step explanation:

Step 1:Sinplify both sides of the inequality

10k <-4k+6

Step 2: Add 4k to both sides

10k + 4k < -4k + 6 + 4k

14k < 6

Step 3:Divide both sides by 14

14k/14 < 6/14

k <3/7

Note:Provided by Mathpapa an Algebra caculator

6 0

3 years ago

The probability of winning a school raffle is 2%. What is the probability of not winning the raffle?

xeze [42]

Answer:

98%

Step-by-step explanation:

If the probability of winning a school raffle is 2%, the probability of not winning the raffle would be 98%.

7 0

2 years ago