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Kazeer [188]
3 years ago
14

Ava wants to ride her bicycle more than 75 miles this week. She has already ridden her bicycle 16 miles. Which inequality could

be used to determine the mean number of miles, m, she would need to ride her bicycle each day for five more days to achieve her goal?
Mathematics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

I think it may be  5m + 16 < 75

Step-by-step explanation:

I don't know if its wrong

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Central City High School's robotics team is at a competition. In the last round, the team earned 80 points for climbing over an
sweet [91]

Answer:

344 = 12*22 + 80

Step-by-step explanation:

They made the ball 22 times

6 0
3 years ago
Liz wants to buy a shirt for $25. How much will Liz's shirt cost in Springfield(4.1%) Round up to the nearest cent? Show your wo
grandymaker [24]
In order to find the total amount of the shirt including tax, first convert the tax into a decimal:
4.1/100 = 0.041 %
Next multiply the cost of the shirt before tax by the tax in decimal form:
25 * 0.041 = 1.025
After that you will add the tax cost and the shirt cost:
25 + 1.025 = 26.025
Finally round to the nearest cent:
26.03
Hope this helps and let me know if you have more questions!
7 0
3 years ago
Read 2 more answers
Solve for j.<br> j/-2+7=-12<br> j=
tangare [24]
J/-2 + 7 = -12 multiply both sides with 2

-j + 14 = -24 move -14 to the other side and change sign

-j= -24 - 14
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j=38




4 0
3 years ago
La adición de dos números es -17. Calcula el Numero Menor, si el mayor es -8
nasty-shy [4]
<h2> <em><u>Podría ser -9</u></em></h2>

Step-by-step explanation:

8 0
3 years ago
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How many minutes he does arm routine and abdominal routine
AlekseyPX
Let x be the amount of time it takes to perform an arm routine and y be the amount of time it takes to perform an abdominal routine.  We see:

4x+y=70
4x+2y=100

Subtracting the second equation from the first gives y=30.  Substituting gives 4x+30=70, so 4x=40 and x=10.

Thus, an arm routine takes ten minutes and an abdominal routine takes thirty minutes.
5 0
3 years ago
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