The equation 2 has a graph which is a straight line.
Why?
We can know which of the given equations has a graph which is a straight line just checking the exponents of the variables.
We must remember that every variable that has an exponent equal or higher than 2 (quadratic) will not have a straight line as a graphic.
So, checking the exponents from the given equations, we have:

Hence, we can see that the only equation that has a linear term (straight line graph), is the second equation.
Have a nice day!
Note: I have attached a image for better understanding.
9) 147
10) 145
greatest common factor is 14 I think
Answer: c
<u>Step-by-step explanation:</u>
When multiplying matrices, multiply ACROSS with the left matrix and DOWN with the right matrix.
![\text{Example}:\left[\begin{array}{cc}a&b\\c&d\end{array}\right] \times \left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}ax+by\\cx+dy\\\end{array}\right]](https://tex.z-dn.net/?f=%5Ctext%7BExample%7D%3A%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dax%2Bby%5C%5Ccx%2Bdy%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}5&2\\3&-1\end{array}\right] \times \left[\begin{array}{c}2\\3\end{array}\right] =\left[\begin{array}{c}5(2)+2(3)\\3(2)-1(3)\\\end{array}\right] = \left[\begin{array}{c}16\\3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%262%5C%5C3%26-1%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C3%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D5%282%29%2B2%283%29%5C%5C3%282%29-1%283%29%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D16%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
Answer:14/20
Step-by-step explanation: