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Cloud [144]
3 years ago
9

I need to find the x pls help and show work

Mathematics
2 answers:
Alexandra [31]3 years ago
7 0

Answer:

Start giving more points

Step-by-step explanation:

plus i needed the points

Firlakuza [10]3 years ago
7 0

Answer:

x=143

Step-by-step explanation:

deNew image over pre-image so 52/4 would equal x/11 because those sides correspond, then cross multiply to get 572 equals 4x then divide each side by 4 to get x=143

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Which of the given expressions results in 0 when evaluated at x = 5?
galben [10]

Answer:

B

Step-by-step explanation:

Look for an expression with (x - 5 ) as this will give zero when x = 5, that is

x - 5 = 5 - 5 = 0

The only expression with a factor of (x - 5 ) is B

7 0
3 years ago
For which rational expression is –2 an excluded value of x?
Kipish [7]

Answer:

option a is the answer

Step-by-step explanation:

put the value of x in each expression as x = -2

you'll see that in option a the expression becomes

\frac{x - 3}{ {x}^{2}  - 4}   =   \frac{ - 2 - 3}{ {( - 2)}^{2}  - 4}  \\  =  \frac{ - 5}{4 - 4} \\  =   \frac{ - 5}{0}

which is not defined. hence -2 is excluded value

5 0
3 years ago
Which graph represents a function with direct variation
vazorg [7]

Answer:

WHere are the graphs

Step-by-step explanation:

:)

4 0
3 years ago
URGENT!!! WILL MARK BRAINLIEST
Evgesh-ka [11]

Answer: 0.75

Step-by-step explanation:

8 0
3 years ago
In △ABC, point P∈ AC with AP:PC=1:3, point Q∈AB so that AQ:QB=3:4, Find the ratios APBQ : APBC and AAQP : AABC.
weqwewe [10]

Answer: The  ratios APBQ : APBC=4:21 and AAQP : AABC= 3:28

Explanation:

Here, ABC is a triangle where, P and Q are the midpoints of the edges AC and AB respectively,

Now, according to the question ,AP:PC=1:3 let AP=x and PC=3x where x is any real number. Thus, AC=AP+AC= x+3x= 4x

Similarly,  AQ:QB=3:4 let AQ=3y and QB=4y where y is also any real number. Thus, AB=AQ+QB=3y+4y=7y

Since, \frac{AP.BQ}{AP.BC} =\frac{AP.BQ}{AB.PC} =\frac{x.4y}{7y.3x} =\frac{4xy}{21xy} =\frac{4}{21}

And, \frac{AA.QP}{AA.BC} =\frac{AQ.AP}{AB.AC} =\frac{3y.1x}{7y.4x} =\frac{3xy}{28xy} =\frac{3}{28}

5 0
4 years ago
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