A freight train from city A to city B and a passenger train from city B to city A left the cities at the same time, at 10 am, he
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Answer:
We have a strong negative relationship between the variables.
Step-by-step explanation:
Given two random variables X and Y, it is possible to calculate the covariance as Cov(X, Y) = E(XY)-E(X)E(Y). We have E(X)=5, E(Y)=6 and E(XY)=21. Therefore Cov(X,Y)=21-(5)(6)=21-30=-9. On the other hand, we know that the correlation of X and Y is the number defined by and because in this particular case we have V(X)=9 and V(Y)=10, we have
= -0.9487. Therefore, we have a strong negative relationship between the variables.
Answers:
Part 1: 5
Part 2: 4/6 m
Part 3:
Part 4: 5
Part 5: 4/6 m
Step By Step Explanation:
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