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docker41 [41]
3 years ago
6

Solve for x. Enter the solutions from least to greatest. 5x^2 - 20x + 15 = 0

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0

Answer:

  • x = {1, 3}

Step-by-step explanation:

  • 5x² - 20x + 15 = 0
  • x² - 4x + 3 = 0
  • x² - 4x + 4 = 1
  • (x - 2)² = 1
  • √(x - 2)² = √1
  • x - 2 = ± 1
  • x = 2 ± 1
  • x = 1, x = 3
MrMuchimi3 years ago
7 0
Yea it is correct the answer is x=3
X=1

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Please someone do this for me
nlexa [21]

Answer:

A = -12

B = -8

C = -4

Step-by-step explanation:

y=2x-8

x = -2

y=2(-2)-8=-4-8=-12

A = -12

x = 0

y = 2 (0)-8=-8

B = -8

x = 2

y = 2 (2) -8 = 4-8 = -4

C = -4

Hope this helps

8 0
2 years ago
a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream
Nonamiya [84]

the coordinates where the bridges must be built is (3,-6) and (6,3) .

<u>Step-by-step explanation:</u>

Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:

Basically we need to find values of x for which f(x) = g(x) :

⇒ f(x)-g(x)=0

⇒ 3x^2- 24x + 39-(3x - 15 ) =0

⇒ 3x^2- 24x + 39-3x + 15  =0

⇒ 3x^2- 27x + 54  =0

⇒ x^2- 9x + 18  =0

⇒ x^2- 6x-3x + 18  =0

⇒ x(x- 6)-3(x - 6)  =0

⇒ (x-3)(x- 6)  =0

⇒ x=3 , x=6

Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6

Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3

Therefore , the coordinates where the bridges must be built is (3,-6) and (6,3) .

7 0
4 years ago
Find the point in the first octant where the tangent plane to x2+116y2+14z2=1 is parallel to the plane x+y+z=10
Stella [2.4K]
2x+3=yx bc it makes the most sence
7 0
3 years ago
Pls help.................
Crank
The correct answer is u multiple it by 5 then u move it directions
7 0
3 years ago
Read 2 more answers
At school, the maximum number of students that can be in a classroom is 21. If there are 16 students signed up for the geometry
nalin [4]

Step-by-step explanation:

Simple

We will subtract

21 - 16 = 5

So 5 more students can join the class

7 0
4 years ago
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