The number of rounds that can be played is given by the product of three
and the least number of tokens a player has at the start.
<h3>Response;</h3>
<h3>Reasons for arriving at the above value;</h3>
A round is when the player with the most tokens gives one token to each of the other players, and one placed in the discard pile, we have;
<h3>First three round</h3>
17 - 3 = 14
16 + 1 = 17
15 + 1 = 16
17 - 3 = 14
14 + 1 = 15
16 + 1 = 17
17 - 3 = 14
14 + 1 = 15
15 + 1 = 16
The above values follow a number series such that we have;
<h3>Fourteenth three rounds</h3>
4 - 3 = 1
2 + 1 = 3
3 + 1 = 4
4 - 3 = 1
1 + 1 = 2
3 + 1 = 4
4 - 3 = 1
2 + 1 = 3
1 + 1 = 2
<h3>Fifteenth three rounds</h3>
3 - 3 = 0
1 + 1 = 2
2 + 1 = 3
3 - 3 = 0
0 + 1 = 1
2 + 1 = 3
3 - 3 = 0
0 + 1 = 1
1 + 1 = 2
Therefore, after the fifteenth three rounds, which is 15 × 3 = <u>45 rounds</u> Ava runs out of token, ending the game.
Learn more about number series here:
brainly.com/question/4163549
x^2 - x - 2 is the answer
Hey!
Myles had 185 songs. He purchased 30 extra songs.
30 ÷ 185 = 0.162 = 16.2%
Answer ⇒ 16.2%
Hope this helps! :)
Answer:
-1/8 is the answer
Step-by-step explanation:
1.) 1st we have to take 1/2x and make the bottom number 4. so we multiply by 2 and you should get 2/4.
2.) so now the equation should be 3/4x + 5 -2/4x = 3. now you take 3/4x and -2/4x and subtract them and you should get 1/4x.
3.) now the equation should look like 1/4x + 5 = 3. now we need to get all whole numbers to one side. so we will subtract 5 from 5 and that will cancel it out and we need to do that to both sides. so we will subtract 5 from 3 and you will get -2.
4.) now the equation should look like 1/4x = -2. now you put a 1 under the 2 to make it a fraction. it should look like 2/1 and then you are going to flip it because that is how you divide fractions. so now your equation should look like 1/4x = 1/2. now you multiply strait across both bottom and top. and you will get x = -1/8 and that is your answer.
hope this helped!
p.s it would be cool if you gave me brainliest.
