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SCORPION-xisa [38]
3 years ago
7

Constant of Variation

Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

B. f and g are reflections of each other about the y-axis.

Step-by-step explanation:

I calculated it logically

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a 15-foot telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 degre
scoundrel [369]

Answer:

The length of the wire is 22.42 feet

The distance from the base of the pole to the spot where the wire touches the ground is 16.66 feet

Step-by-step explanation:

* Lets explain the situation in the problem

- The telephone pole , the wire and the ground formed a right triangle

- The wire is the hypotenuse of the triangle

- The height of the telephone pole and the distance from the base of

 the pole to the spot where the wire touches the ground are the legs

 of the triangle

- The angle between the wire and the ground is 42°

- The angle 42° is opposite to the height of the telephone pole

- The height of the telephone pole is 15 feet

* Lets use the trigonometry functions to find the length of the wire

 (hypotenuse) and the distance from the base of the pole to the spot

 where the wire touches the ground

∵ sin Ф = opposite/hypotenuse

∵ Ф = 42° and its opposite side = 15 feet

∴ sin 42 = 15/hypotenuse ⇒ by using cross multiplication

∴ sin 42° (hypotenuse) = 15 ⇒ divide both sides by sin 42

∴ hypotenuse = 15/sin 42° = 22.42 feet

∵ The length of the wire is the hypotenuse

∴ The length of the wire is 22.42 feet

∵ The distance from the base of the pole to the spot where the wire

   touches the ground is the adjacent side to the angle 42°

∵ tan Ф = opposite/adjacent

∴ tan 42° = 15/adjacent ⇒ by using cross multiplication

∴ tan 42° (adjacent) = 15 ⇒ divide both sides by sin 42

∴ adjacent = 15/tan 42° = 16.66 feet

∵ The adjacent side is the distance from the base of the pole to the

  spot where the wire touches the ground

∴ The distance from the base of the pole to the spot where the wire

   touches the ground is 16.66 feet

7 0
4 years ago
three tickets to attend an off-broadway show cost $81 , 4 tickets cost $108, and 5 ticckets cost $135. A. show that the relation
alex41 [277]
1 ticket costs $27, 2 tickets cost $54, 3 cost $81, 4 cost $108, and 5 cost $135.

There is a $27 difference between each ticket above or below
4 0
3 years ago
Read 2 more answers
Find the area of the figure. (Sides meet at right angles.)
Lubov Fominskaja [6]

Answer:

the area is 68 feet

Step-by-step explanation:

-first pretend that one spot is filled and if you do that the whole rectangle is 8 by 10.

- the area of something is length times width and so 8 times 10 is 80

- however, we can't pretend that we don't have a hole anymore so to figure out that tiny rectangles area we have to find its width and length which is 4 and 3.

- 4 times 3 is 12 and since we have that we subtract 12 from 80 and we get 68.

3 0
3 years ago
Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right
Jet001 [13]

Answer:

Option B.

Step-by-step explanation:

It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.

RT is altitude on side SQ, ST=9, TQ=16 and SR=x.

In ΔSRQ and ΔSTR,

m\angle S=m\angle S           (Reflexive property)

m\angle R=m\angle T           (Right angle)

By AA property of similarity,

\triangle SRQ\sim \triangle STR

Corresponding parts of similar triangles are proportional.

\dfrac{SR}{SQ}=\dfrac{ST}{SR}

Substitute the given values.

\dfrac{x}{9+16}=\dfrac{9}{x}

\dfrac{x}{25}=\dfrac{9}{x}

On cross multiplication we get

x^2=25\times 9

x^2=225

Taking square root on both sides.

x=\sqrt{225}

x=15

The value of x is 15. Therefore, the correct option is B.

7 0
4 years ago
Read 2 more answers
Two runners start 30 kilometers apart and run toward each other. They meet after 3 hours. One runner runs 2 kilometers per hour
dmitriy555 [2]
D. 4km/hr and 6 km/hr
5 0
3 years ago
Read 2 more answers
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