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mezya [45]
3 years ago
7

What does 5/12 - 1/3 equal?

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer: 1/12

Step-by-step explanation:

5/12 - 1/3

1/3 = 4/12

5/12 - 4/12 = 1/12

rosijanka [135]3 years ago
6 0
The answer to 5/12-1/3 equals 1/12
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Find the radius of a circle with a circumference of 35 pie yards
natita [175]

Answer:

Using the formula

C=2πr

Solving for r

r=C

2π=35

2·π≈5.57042

Step-by-step explanation:

8 0
2 years ago
CLICK HERE IF YOU HAVE BIG FEET <br><br> Using the function g( x) = -2 x – 11, calculate g(-3).
Leokris [45]

════════ ∘◦❁◦∘ ════════

<h3>Answer = -5</h3>

════════════════════

<h3>Known</h3>

g(x) = -2x - 11

════════════════════

<h3>Question</h3>

g(-3) = ..?

════════════════════

<h3>Way to do</h3>

#since x inside (x) change into (-3) then it means that you only need to change x into -3

g(-3) = -2(-3) - 11

g(-3) = 6 - 11

g(-3) = -5

════════════════════

6 0
3 years ago
Suppose two linear equations have the same slope. Is it true that the point (3, 4) is the only point that satisfies both equatio
IrinaVladis [17]
No but it is true that the two equations are parallel.
8 0
2 years ago
Suppose xy=4 and dy/dt=-2. Find dx/dt when x=-3
nirvana33 [79]
Dy/dx = dy/dt  *   dt/dx

xy = 4

y + x(dy/dx) = 0      by implicit differentiation. 

x(dy/dx) = -y

dy/dx = -y/x

<span>dy/dx = dy/dt  *   dt/dx             dy/dt = -2
</span>
<span>-y/x = -2 *   dt/dx
</span>
y/(2x) = dt/dx

dt/dx =  y/(2x)

dx/dt = 2x/y
  
When x = -3,   xy = 4,  y = 4/x = 4/-3 = -4/3

dx/dt = 2*-3/(-4/3) = -6 *-3/4 = 18/4 = 9/2 = 4.5

dx/dt = 4.5
3 0
3 years ago
Read 2 more answers
Geometry help needed!
salantis [7]

Answer:

AC Midpoint (2,0)-

CB Midpoint (5,-4)

midlength is 5

Step-by-step explanation:

midpoint formula (\frac{x_{1}+x_{2}  }{2} ,\frac{y_{1} +y_{2} }{2})

A(2,4) C(2,-4)

\frac{2+2}{2} =\frac{4}{2}=2\\\frac{4-4}{2}  =\frac{0}{2} =0

(2,0)

C(2,-4) B(8,-4)

\frac{8+2}{2} =\frac{10}{2} =5

\frac{-4-4}{2} =\frac{-8}{2} =-4  midpoint is  (5,-4)

Distance between the 2 midpoints is the midsegment

(2,0) and (5,-4)

d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})  ^{2}   }

d=\sqrt{(5-2)^{2} +(-4-0)^{2}  } \\d=\sqrt{3^{2} +(-4^{2})\\ } \\d=\sqrt{x} 9+16\\d=\sqrt{25} \\d=5

3 0
3 years ago
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