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Masja [62]
3 years ago
9

Given f(x) = x^2 + 3 , work out the value of f(4)

Mathematics
2 answers:
Tamiku [17]3 years ago
7 0

Answer: 19

Step-by-step explanation:

f(4)=(4)^2+3=16+3=19

kondaur [170]3 years ago
5 0

Answer:

f(4) = 19

Step-by-step explanation:

f(x) = x^2 + 3

plug in 4 for the xs

f(4) = 4^2 + 3

f(4) = 16 + 3

f(4) = 19

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A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
3 years ago
Adele opens an account with $120 and deposits $45 a month. Kent opens an account with $80 and also deposits $45 a month. Will th
Alina [70]
No they wont have the same amount because adele will have 50 dollars more each month
3 0
4 years ago
Bus A travels according to the function y = 125/5x where y is distance traveled in miles and x is time in hours. Bus B travels a
Yuki888 [10]

Answer:

Bus B travel faster

Step-by-step explanation:

The graph of the question in the attached figure

we know that

the linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

x ---> is the time in hours

y ---> is the distance in miles

In this problem we have

Bus A

y=\frac{125}{5}x

The slope of the linear equation represent the speed of the bus

so

The speed of bus A is

\frac{125}{5}=25\ miles/hour

Bus B

Find  the slope

take two points from the graph

(0,0) and (3,200)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{200-0}{3-0}

m=66.67\ \frac{miles}{hour}

Compare the slope Bus A with the slope Bus B

66.67\ \frac{miles}{hour} > 25\ \frac{miles}{hour}

therefore

Bus B travel faster

6 0
4 years ago
Negative five ex is greater than or equal to 40
jonny [76]

-5x≤40 would be the answer

5 0
3 years ago
Please hurry I'm being timed!
rjkz [21]

Answer:

t=44

Step-by-step explanation:

19+25=44

5 0
3 years ago
Read 2 more answers
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