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Butoxors [25]
3 years ago
7

What is the correct factored for of x^2-9/x-3 to show a common factor can be divided out?

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

Answer:

should be x^2-9/x-3

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-25

Step-by-step explanation:

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Mariana [72]

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Step-by-step explanation:

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8 0
2 years ago
Triangle MNP has side lengths 3.5 cm, 4.1 cm, and 4.3 cm. A triangle with what side lengths would be similar to triangle MNP?
atroni [7]

Answer:

Option 1,

The triangle MNP is similar to the triangle with side lengths 35 cm, 41 cm, 43 cm

Step-by-step explanation:

Given triangle MNP has side lengths 3.5 cm, 4.1 cm, and 4.3 cm. we have to find the similarity triangle sides from the given option.

As we know, the two triangles are similar if the measures of the corresponding sides of two triangles are proportional.

For the first option: 35 cm, 41 cm, 43 cm

\frac{3.5}{4.1}=\frac{4.1}{41}=\frac{4.3}{43}=\frac{1}{10}

which shows that the sides are proportional.

we have to choose only one option ∴ we needn't have to check the others

Hence, the triangle MNP is similar to the triangle with side lengths 35 cm, 41 cm, 43 cm

6 0
3 years ago
Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8
goblinko [34]
\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y  = \frac{17}{14} } \atop {x+7y=8}} \right.

To solve this system by substitution, first isolate x in the second equation.

x+7y=8
x+7y-7y=8-7y
x=8-7y

Now, plug this expression (8-7y) for x in the top equation to solve for y.

\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}
3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}
72-63y+8y=17
72-55y=17
-55y=17-72
-55y=-55
y=1

Now that you have y, plug it into the second equation and solve for x.

x+7y=8
x+7(1)=8
x+7=8
x=1

Last step is to plug your x- and y-values in to both equations to check your work.

\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}

\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ;  \frac{1}{3} * \frac{8}{8} = \frac{8}{24}

\frac{9}{24} + \frac{8}{24} = \frac{17}{24}  <--True

1+7(1)=8
1+7=8   <--True

Answer:
x=1 \\ y=1
5 0
3 years ago
How many times greater is the value of the 5 in 503 than the value of the 5 in 53?
disa [49]

Answer:

10 times greater

Step-by-step explanation:

Because value of 5 in 503 is 5*100

Then the value of 5 in 53 is 5*10

So then value of 5 in 503 is 10 times greater than the value of 5 in 53

I hope this helps

7 0
3 years ago
Read 2 more answers
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