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4 years ago

9

Maya received a $70 gift card for a coffee store she used it in buying some coffee that costs $7.71 per pound. After buying the

coffee she had $23.74 left on her card how many pounds of coffee did she buy

2 answers:

Helga [31]4 years ago

8 0

Answer: 6

Step-by-step explanation:

70-23.74=46.26

46.26/7.71=6

tester [92]4 years ago

8 0

Hey there!

To find how many pounds of coffee she bought, we first need to figure out how much money she spent in total. To do so, we’ll subtract $70 & $23.74

70 - 23.74 = 46.26

So, she spent $46.26. Now, we divide $46.26 by how much each pound of coffee costs ($7.71) and that will give us the answer

46.26 ÷ 7.71 = 6

Therefore, she bought 6 pounds of coffee

Hope this helps you!

God bless ❤️

Brainliest would be appreciated

xXxGolferGirlxXx

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Simplify the following surds :<br><br> 1) 2√21 × √27 ÷ √343<br> 2) 7√5 × √125 ÷ 2√27

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Answer:

1) $\frac{18}{7}$

2) $\frac{175\sqrt{3}}{18}$

Step-by-step explanation:

* Lets explain how to simplify a square root

1)

∵ $2\sqrt{21}$ × $\sqrt{27}$ ÷ $\sqrt{343}$

∵ $\sqrt{21}=\sqrt{3}$ × $\sqrt{7}$

∴ $2\sqrt{21}$ = $2\sqrt{3}$ × $\sqrt{7}$

∵ $\sqrt{27}$ = $\sqrt{3}$ × $\sqrt{3}$ × $\sqrt{3}$

∵ $\sqrt{3}$ × $\sqrt{3}$ = 3

∴ $\sqrt{27}$ = $3\sqrt{3}$

∴ $2\sqrt{21}$ × $\sqrt{27}$ =

$2\sqrt{3}$ × $\sqrt{7}$ × $3\sqrt{3}$

∵ $\sqrt{3}$ × $\sqrt{3}$ = 3

∵ 2 × 3 × 3 = 18

∴ $2\sqrt{21}$ × $\sqrt{27}$ = $18\sqrt{7}$

∵ $\sqrt{343}$ = $\sqrt{7}$ × $\sqrt{7}$ × $\sqrt{7}$

∵ $\sqrt{7}$ × $\sqrt{7}$ = 7

∴ $\sqrt{343}$ = $7\sqrt{7}$

∵ $2\sqrt{21}$ × $\sqrt{27}$ ÷ $\sqrt{343}$ =

$18\sqrt{7}$ ÷ $7\sqrt{7}$

∵ $\sqrt{7}$ ÷ $\sqrt{7}$ = 1

∴ $2\sqrt{21}$ × $\sqrt{27}$ ÷ $\sqrt{343}$ =

$\frac{18}{7}$

2)

∵ $7\sqrt{5}$ × $\sqrt{125}$ ÷ $2\sqrt{27}$

∵ $\sqrt{125}$ = $\sqrt{5}$ × $\sqrt{5}$ × $\sqrt{5}$

∵ $\sqrt{5}$ × $\sqrt{5}$ = 5

∴ $\sqrt{125}$ = $5\sqrt{5}$

∴ $7\sqrt{5}$ × $\sqrt{125}$ =

$7\sqrt{5}$ × $5\sqrt{5}$

∵ $\sqrt{5}$ × $\sqrt{5}$ = 5

∴ $7\sqrt{5}$ × $\sqrt{125}$ = 7 × 5 × 5 = 175

∵ $2\sqrt{27}$ = $2\sqrt{3}$ × $\sqrt{3}$ × $\sqrt{3}$

∵ $\sqrt{3}$ × $\sqrt{3}$ = 3

∴ $2\sqrt{27}$ = $6\sqrt{3}$

∴ $7\sqrt{5}$ × $\sqrt{125}$ ÷ $2\sqrt{27}$ =

175 ÷ $6\sqrt{3}$ = $\frac{175}{6\sqrt{3}}$

∵ $\frac{175}{6\sqrt{3}}$ not in the simplest form because

the denominator has square root

∴ Multiply up and down by $\sqrt{3}$

∴ $\frac{175}{6\sqrt{3}}$ = $\frac{175\sqrt{3}}{6\sqrt{3}*\sqrt{3}}$

∴ $\frac{175}{6\sqrt{3}}$ = $\frac{175\sqrt{3}}{18}$

∴ $7\sqrt{5}$ × $\sqrt{125}$ ÷ $2\sqrt{27}$ =

$\frac{175\sqrt{3}}{18}$

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