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Ket [755]
3 years ago
10

PLEASE PLEASE PLEASE HELP MEE!!!!!!!!!!!!!!!!

Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

It is C

Step-by-step explanation:

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Find the distance along an arc on the surface of the earth that subtends a central angle of 6 minutes (1 minute = 1/60 degree).
bazaltina [42]

Answer:

6.914miles (to 3 decimal places)

Step-by-step explanation:

Length of an arc = θ/360 *2πr

angle subtended by arc at the center of the earth = 6 minutes

1 minute =1/60 degree

6 minute= 6/60 degree =0.1°

θ=0.1°

radius of earth = 3960 miles

distance along the arc = \frac{0.1}{360}*2\pi  *3960

    =6.9142857143miles

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3 years ago
Which equation represents a nonproportional relationship?
Montano1993 [528]
C. If you have to add on a number it is nonproportional
5 0
3 years ago
What's 5 divided by 3 1/3?
Dafna11 [192]

Answer: 3/2

Step-by-step explanation:

We can start by converting 3 1/3 to an improper fraction. Since 3 is equal to 9/3, 3 1/3 would be equal to 9/3 + 1/3 = 10/3.

Therefore, we are doing \frac{5}{\frac{10}{3}}.

Dividing 5 by 10/3 is the same as multiplying 5 and the reciprocal of 10/3, which is 3/10.

5*3/10 = 15/10 = 3/2.

6 0
2 years ago
Find each sum or difference for 381 1/10 -214 43/100
BartSMP [9]

Answer:

The circled part is the answer.

6 0
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Read 2 more answers
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
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