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jonny [76]
3 years ago
9

What have you heard about "building your credit score"

Mathematics
2 answers:
EleoNora [17]3 years ago
5 0

Answer:

Yessirr

Step-by-step explanation:

AnnZ [28]3 years ago
3 0

Answer: ”Building your credit score” is what many people try to do and is an important part of your financial health. You want good credit scores because they can unlock many savings and benefits, including access to loans and credit cards with the most favorable terms.

Step-by-step explanation: Establishing a good credit score is one of the most important things you'll ever do. Good credit is essential throughout your life, whether you want to buy a house or car, get insurance or maybe even pay less of a deposit for utilities. It will take about six months of credit activity to establish enough history for a FICO credit score, which is used in 90% of lending decisions. FICO credit scores range from 300-850, and a score of over 700 is considered a good credit score. Scores over 800 are considered excellent. Therefore, 850 would be the best credit score.

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A rectangle has a length four more than
torisob [31]
L ≥ 5w + 4
2(L+w) ≥ 32

L+w ≥ 16

6w + 4 ≥ 16
6w ≥ 12
w ≥ 2

L ≥ 5w + 4
L ≥ 14

If L = 14 and w = 2 then the perimeter is 32.
These are the smallest dimensions that fit the criteria.

Note: If we raise the width by 1 to w = 3
then the length is at least 19. At 19 by 3 we have P = 44
Like would be appreciated!!
8 0
1 year ago
A tree is 12 feet tall. A wire runs from the top of the tree to a point of 6 feet from its base. The wire is square root 180 fee
Artyom0805 [142]
13.42 is how long the wire is to the nearest hundredth of a foot
8 0
4 years ago
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
3 years ago
What is 39,258,365 to the nearest thousand
Gwar [14]
The thousands digit in this numeral is 8. which is also 8,000 . The hundreds digit which is 1 numeral behind the thousands in 300, not over 500 where then the next digit, the thousands cannot be rounded up, so if rounded to the nearest thousands, it will remain 8,000 so it will still be...
39,258,000   and thats it :) thx
8 0
3 years ago
Read 2 more answers
A factory manager is packing engine components into wooden crates to be shipped on a small truck. The truck is designed to hold
Lemur [1.5K]

Answer: 63lbs

Step-by-step explanation:

The truck can only hold 16crates and each crate weigh 12lbs, the total weight of the 16 crates will be 12×16= 192lbs

This shows that the truck can only contain extra load of 1200lbs - 192lbs = 1008lbs (excluding weight of crates).

To get the shipment weigh close to the total of 1200lbs, the truck must be loaded with engine components not more than 1008lbs.

Since we have 16 crates to fill with engine components not more than 1008lb, each crates will therefore must not exceed 1008/16 pounds of engine components which is equivalent to 63lbs.

Therefore, the manager should instruct the workers to put 63lbs of machine components in "each crate" in order to get the shipment weight as close as possible to 1200 lbs.

6 0
4 years ago
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