In order to find out where your holes and asymptotes are is to factor both the top and the bottom of that rational function. The numerator factors to (x+2)(x-2) and the denominator factors to x(x+1)(x-2). So since there is an (x-2) in both the numerator and denominator, that is called a removable discontinuity which we also know as a hole. The other factors in the denominator, the x and the (x+1) are vertical asymptotes, or values of x that make the rational function undefined (you're NEVER allowed to have a 0 in the denominator of a fraction!). So your correct choice is c. The way you find the y coordinate for the hole is to plug in 2 for x and solve it for y. No biggie.
Answer:
a. F = (9/5)(K - 273.15) + 32
b. F = 32°F
Step-by-step explanation:
K=5/9(F−32)+273.15
F = (9/5)(K - 273.15) + 32
F = (9/5)(<u>273.15</u> - 273.15) + 32
F = 32
N
- -76=116
5
If the question gives you another variable, just switch it out with n
You will want to start by making your fractions have the same denominator. To do this, multiply the 2/3 by 2/2, to make it 4/6. Now we have this equation:
-4/6x = 1/6x + 4
Next, subtract 1/6x from both sides:
-5/6x = 4
Finally, multiply both sides by -6/5, and you get your answer:
x = -4.8
Given f(x) =

, find f(x), when x is equal to -1.
Simply, you just need to substitute -1 into the given equation.
f(x) =

f(x) = -1 + 2²
f(x) = -1 + 4
f(x) = 3
The value that completes this table is the last choice, which is
3.