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Fiesta28 [93]
3 years ago
12

Which expressions are equivalent to 2(4f+2g) ?

Mathematics
2 answers:
Andrej [43]3 years ago
7 0

Answer:

C, D, E

Step-by-step explanation:

2(4f + 2g) = 8f + 4g

C: 8f + 4g

D: 4(2f + g) = 8f + 4g

E: 4f + 4f + 4g = 8f + 4g

skad [1K]3 years ago
3 0

Answer:

B, C, D

hope this helps

have a good day :)

Step-by-step explanation:

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A cardboard box without a lid is to be made with a volume of 4 ft 3 . Find the dimensions of the box that requires the least amo
Blababa [14]

Answer:

<h2><em>2ft by 2ft by 1 ft</em></h2>

Step-by-step explanation:

Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;

S  = lw+2wh+2lh ... 1

Given the volume V = lwh = 4ft³ ... 2

From equation 2;

h = 4/lw

Substituting into r[equation 1;

S = lw + 2w(4/lw)+ 2l(4/lw)

S = lw+8/l+8/w

Differentiating the resulting equation with respect to w and l will give;

dS/dw = l + (-8w⁻²)

dS/dw = l - 8/w²

Similarly,

dS/dl = w  + (-8l⁻²)

dS/dw = w - 8/l²

At turning point, ds/dw = 0 and ds/dl = 0

l - 8/w² = 0 and w - 8/l² = 0

l = 8/w²  and w =8/l²

l = 8/(8/l² )²

l = 8/(64/I⁴)

l = 8*l⁴/64

l = l⁴/8

8l = l⁴

l³ = 8

l = ∛8

l = 2

Hence the length of the box is 2 feet

Substituting l = 2 into the function l = 8/w² to get the eidth w

2 = 8/w²

1 = 4/w²

w² = 4

w = 2 ft

width of the cardboard is 2 ft

Since Volume = lwh

4 = 2(2)h

4 = 4h

h = 1 ft

Height of the cardboard is 1 ft

<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>

8 0
3 years ago
The graph shows two lines. Help Plsssss!!!
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

If two lines coincide then the system of linear equations has infinitely many solutions.

5 0
3 years ago
G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.
vova2212 [387]

Answer:

▢ $\overline{DG}$ ≅ $\overline{FG}$

▢ $\overline{DG}$ ≅ $\overline{BG}$

▢ $\overline{GE}$ bisects \displaystyle ∠DEF

▢ $\overline{GA}$ bisects \displaystyle ∠BAF

Step-by-step explanation:

As you can see, angles \displaystyle BAF and \displaystyle DEF form two half-kites, which you should know have <em>two</em><em> </em><em>pairs of</em><em> </em><em>congruent</em><em> </em><em>sides</em>, therefore segments \displaystyle GA and \displaystyle GE are what you call angle bisectours, which is why segments \displaystyle FG, \displaystyle DG, and \displaystyle BG are congruent.

I am joyous to assist you at any time.

4 0
3 years ago
Someone help my sister with her math I’ll give you brainlest.
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9514 1404 393

Answer:

  see attached

Step-by-step explanation:

We're not quite sure what the question is.

It appears you may be interested in the names of the groups of 3 digits. Each such group is called a "period." Each period is named for the place value of its right-most digit.

The period just to the left of the decimal point is the "ones" period. To the left of that is the "thousands" period, and to its left is the "millions" period.

When writing the name of a number, the name of the three digits within a period is given, followed by the period name (if it is greater than "ones"). This continues left to right, until you get to the decimal point. For example, the number shown is ...

  eight hundred sixty-two thousand seven hundred ninety-four

5 0
3 years ago
6. Evaluate f(g(-3)) given the functions below. *
Sholpan [36]

Answer:

21

Step-by-step explanation:

solve g(-3)

2(-3)^2 + 7

25

solve f(25)

25-4

21

6 0
3 years ago
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