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vichka [17]
3 years ago
11

A construction crew is lengthening a road. The road started with a length of 59 miles, and the crew is adding 2 miles to the roa

d each day.
Let L represent the total length of the road (in miles), and let D represent the number of days the crew has worked. Write an equation relating I to
this equation to find the total length of the road after the crew has worked 32 days.
Mathematics
1 answer:
Illusion [34]3 years ago
7 0
The answer is L = 59 + 2(d). If we plug in our numbers, we will get L = 59 + 2(32). 2*32 is 64, and if you add 59 you get 123 miles.

This isn’t apart of the question, but 59 would be the y-intercept. 2 miles per day (2/1) is the slope.
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For Each Data Set, Determine the median, the first and third Quartiles, and the interquartile Range.
inysia [295]
Text per day: median= 26 1st quartile= 19 3rd quartile=38 Interquartile=19 Daily attendance: median=357.5 1st quartile=298 3rd quartile=422 Interquartile= 124
4 0
3 years ago
salini's mother's present age is 8 times salini's present age five years from now salini's age will be 1/4th of of his mother's
choli [55]

Answer:

salini -= 5 years

mother = 40years

Step-by-step explanation:

salini = x \\ mother =8x \\ x + 5 = 1 \: of \: 8x \\  x + 5 = 2x \\ 5 = x

5 = x

then you equate the values of x

8 0
3 years ago
Suppose that receiving stations​ X, Y, and Z are located on a coordinate plane at the points ​(4​,5​), ​(-6​,-6​), and ​(-14​,2​
Lilit [14]

Answer:

  (-2, -3)

Step-by-step explanation:

A careful graph shows the point (-2, -3) is at the intersection of the circles whose radii are the given distances from the receiving stations.

_____

The simultaneous equations for the circles can be solved algebraically.

The epicenter is 10 units from X, so lies on the circle ...

  (x -4)^2 +(y -5)^2 = 10^2

  x^2 -8x +16 +y^2 -10y +25 = 100

  x^2 +y^2 -8x -10y = 59

__

The epicenter is 5 units from Y, so lies on the circle ...

  (x +6)^2 +(y +6)^2 = 5^2

  x^2 +12x +36 +y^2 +12y +36 = 25

  x^2 +y^2 +12x +12y = -47

__

The epicenter is 13 units from Z, so lies on the circle ...

  (x +14)^2 +(y -2)^2 = 13^2

  x^2 +28x +196 +y^2 -4y +4 = 169

  x^2 +y^2 +28x -4y = -31

__

Subtracting the second equation from each of the other two, we get ...

  (x^2 +y^2 -8x -10y) -(x^2 +y^2 +12x +12y) = (59) -(-47)

  -20x -22y = 106 . . . . eq1 -eq2

  (x^2 +y^2 +28x -4y) -(x^2 +y^2 +12x +12y) = (-31) -(-47)

  16x -16y = 16 . . . . . . . .eq3 -eq2

These simultaneous linear equations can be solved a variety of ways. We might use substitution:

  x = y+1 . . . . . from eq3 -eq2 divided by 16

  10(y +1) +11y = -53 . . . . . from eq1 -eq2 divided by -2

  21y = -63 . . . . . . . . . . . . simplify, subtract 10

  y = -3

  x = y+1 = -2

The epicenter is located at (x, y) = (-2, -3).

8 0
3 years ago
Please help me with 7 and 10!! i’ll mark you brainliest:)
Irina-Kira [14]

Answer:

7. 18,480 feet

10. (a.) 1.5     (b.) 150%     Sorry I don't know the answers to c & d.

Step-by-step explanation:

7. \frac{3.5 miles}{1 ft.} × \frac{5,280 ft.}{1 mile} = 18,480ft.

Hope this helps!

7 0
4 years ago
State the independent variable and dependent variable and find the slope.
Rudik [331]
Time is your independent variable, and snowfall is your dependent variable.

Slope can be found by calculating ∆y/∆x:
x =  \frac{0.06 - 0.02}{3 - 1}  \\ x =   \frac{0.04}{2}  \\ x = 0.02

Snowfall will accumulate 0.02 m every hour.
4 0
3 years ago
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