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serg [7]
4 years ago
6

Solve for f.

Mathematics
1 answer:
Delvig [45]4 years ago
8 0
<span>Solve for f.

h = f² + 2g

</span>h= f^2+2g \\  \\ h-2g=f^2 \\  \\  \boxed{ \pm\sqrt{h-2g}= f}<span>
</span>
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Find the equation of the line parallel to -5x+2y=12 and through (10,21)
Ksivusya [100]

y=5/2x-4

Step-by-step explanation:

im pretty sure

8 0
3 years ago
Read 2 more answers
Evaluate.<br> (x + 4). 2 - x for x = 6<br> 54<br> 74<br> 0<br> 14
Scrat [10]

Answer: 74

Step-by-step explanation:

Substitute x=6 into the expression

(x+4) . 2^3 -6

Add the numbers

(6+4) . 2^3- 6

10 x 2^3 -6

Evaluate the power

10 x 2^3 -6

10 x 8-6

Multiply the numbers

10 x 8-6

80-6

Subtract the numbers

80-6

74

3 0
4 years ago
Factorise the following expression :​
Bas_tet [7]

Answer:

x³+2x²+5x+10

x²(x+2)+5(x+2)

(x+2)(x²+5)

a³-a²b²-ab+b³

a²(a-b²)-b(a-b²)

(a-b²)(a²-b)

5 0
3 years ago
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Is it true that: If f"(c) &gt; 0, then the slope of
zheka24 [161]

Answer:

yes

Step-by-step explanation:

the FIRST derivative of a function tells us the slope of a tangent line to the curve at any point. if is positive, then the curve must be increasing. If is negative, then the curve must be decreasing.

the SECOND derivative gives us the slope of the slope function (in other words how fast the slope of the original function changes, and if it is accelerating up - positive - or if it is avengers down - negative).

so, the first derivative would be fully sufficient to get the answer of if the slope of the function at that point is positive or negative.

but because it is only a "if" condition and not a "if and only if" condition, the statement is still true.

there are enough cases, where the slope is positive, but the second derivative is not > 0 (usually = 0).

but if even the second derivative is positive, then, yes, the slope of the original function must be positive too.

3 0
2 years ago
Can someone please help me with this thank you!!
kotykmax [81]

Answer:

1. add up all of the arcs.

2x+3x+4x-8+x-12

2. all of the arcs equal 360

2x+3x+4x-8+x-12=360

3. Find x

10x-20=360, x=38

4. angle LTE is equal to half of the sum of the intercepted arcs.

.5(arc LE +GF)

5. plug in LE +GF with x

.5(76+144)

LTE=110

8 0
4 years ago
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