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kap26 [50]
3 years ago
8

Write the output of the following program:

Computers and Technology
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

Expression A

Explanation:

In this Pseudocode, the output would be 100. This is because the code is looping from 1 to 20 and adding together all of the odd numbers between 1 and 20. Since it is checking to make sure that the remainder of each number is not equal to 0 which would indicate an odd number, and if it is odd then it adds it to the variable S. Therefore, the odd numbers between 1 and 20 are the following...

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 100

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Frank accidently overwrote his old document with a new document of the same name. He'd like to get his old document back. What f
Archy [21]

Answer:

the recycle bin?

Explanation:

usually when you overwrite something or delete it, it doesn't get entirely deleted rather stored in the recycle bin on your desktop i believe, and so you could retrieve applications through there

4 0
3 years ago
(Find the number of uppercase letters in a string) Write a recursive function to return the number of uppercase letters in a str
Leokris [45]
Def countUppercase(s):
count=0
for i in s:
if i.isupper():
count+=1
s=s.replace(i, "")
else:
s=s.replace(i, "")
countUppercase(s)
return count

element=input("Enter the string: ")
string=countUppercase(element)
print("\nNumber of upper letter in the string: ",string)

3 0
3 years ago
The motherboard
Ksju [112]

Answer:

a:(allows the different parts of a computer to communicate)

Explanation:

The motherboard is the main command center for the whole pc which recieves your inputs and responds by sending outputs...

3 0
3 years ago
What are hard ware and software requirments in multimedia computer system
marishachu [46]

Answer:

Some hardware requirement: Monitor, keyboard, mouse, sound card, memory, processor, graphics display card. Some software requirement: Windows XP/Vista, Video for Windows, Quicktime.

Explanation:

BRAINLEST

4 0
3 years ago
Give an efficient algorithm to find all keys in a min heap that are smaller than a provided value X. The provided value does not
viva [34]

Answer:

The algorithm to this question as follows:

Algorithm:

finding_small_element(element,Key xa) //defining method that accepts parameter

{

if (element.value>= xa) //check value

{

//skiping node

return;  

}

print(element.value);//print value

if (element.left != NULL) //check left node value

{

finding_small_element(element.left,xa); //using method

}

if (element.right != NULL) //check right node value

{

finding_small_element(element.right,xa); //using method

}

}

Explanation:

In the above pre-order traversing algorithm a method  "finding_small_element" is defined, that accepts two parameter, that is "element and ax', in which "element" is node value and ax is its "key".

  • Inside this if block is used that check element variable value is greater then equal to 0.
  • In the next step, two if block is defined, that check element left and the right value is not equal to null, if both conditions are true, it will check its right and left value. In this algorithm, there is no extra need for traversing items.
3 0
3 years ago
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