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RSB [31]
3 years ago
15

Help me please with this I will give brainliest

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

1. 18

2. 72

3. 90%

Step-by-step explanation:

For number 1

To find percentage you multiply the total number of kids with the percentage.

To do this you have to convert the percent into a decimal by moving the dot 2 times from its original location Ex. 20% = .20 as 20 would look like 20.00 in decimal form.

So .20 x 90 = 18

For number 2

Subtract 18 and 90 to find the remanding kids

For number 3

Divide 72 and 90. Make sure the lower number is being divided.

The answer you will get is .8 so move the decimal back two times because you are converting it to a percentage."

You will then get 80.00 as an answer then from there turn it to a percentage

80%

Hope this helps!

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kkurt [141]

Answer:5+4 = 9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What two numbers multiply to 10 and add to -29 ?
Degger [83]
Xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

so
x^2+29x+10=0
a=1
b=29
c=10
x=\frac{-29+/- \sqrt{(-29)^{2}-4(1)(10)} }{2(1)}
x= \frac{-29+/- \sqrt{841-40} }{2}
x= \frac{-29+/- \sqrt{801} }{2}
x= \frac{-29+/- 3\sqrt{89} }{2}

x= \frac{-29- 3\sqrt{89} }{2} or \frac{-29+ 3\sqrt{89} }{2}
those are the 2 numbers
aprox=-28.65 and -0.349


5 0
2 years ago
Read 2 more answers
A little help??????????????
Paul [167]

Answer:

b for the first one and A for the second

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Ending time 6:30, elapsed time 37 minutes
Nastasia [14]

Answer:

5:53

Step-by-step explanation:

The original time would be 37 minutes before 6:30 so you would subtract 37 minutes from 6;30. So 6:30 minus 30 would be 6 and you would have 7 left over so 6:00 minus 7 minutes would be 5:53

6 0
2 years ago
Explain how System 1 becomes equivalent to System 2.
Nostrana [21]

Answer:

\left\{\begin{array}{ccc}(A+L)x+(B+M)y=C+N\\Ax+By=C\end{array}\right

<h3>A.The first equation in System 2 is the sum of the equations in System 1. The second equation in System 2 is the first equation in System 1.</h3>

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}Ax+By=C\\Lx+My=N\end{array}\right}\qquad\text{add both sides of the equations}\\(Ax+Lx)+(By+My)=C+N\qquad\text{distributive}\\(A+L)x+(B+M)y=C+N

5 0
3 years ago
Read 2 more answers
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