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choli [55]
3 years ago
13

Are 6/8 and 9/12 proportional?

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
The answer would be yes, 3/4=3/4
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PLZ help with this it should be super easy <br> plz and thx
kherson [118]

Answer:

-m²+81

Step-by-step explanation:

Hello There!

9x-m=-9m

9x9=81

mx-m=-m²

9xm=9m

9m-9m=0

we would be left with

-m²+81

5 0
3 years ago
Read 2 more answers
In the figure, qj= 2x+100 and sj=6x+52 what is sj ?
Phoenix [80]

Answer:

124

Step-by-step explanation:

2x+100=6x+52

solve for variable x = 12

plug it in

2(12)+100

sj= 124

5 0
4 years ago
6. The functions off and g are defined by f(x) = 4x + 2 and g(x) = x². Calculate for:
likoan [24]

Answer:

\boxed{66}

Step-by-step explanation:

if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) =  {4}^{2}  \\ f[g(4)]  = 4( {4}^{2} ) + 2 \\ f[g(4)]  = 4(16) + 2 \\ f[g(4)]  =64 + 2 \\   f[g(4)]  =  \boxed{66}

3 0
3 years ago
Simplify the expression the root of negative sixteen all over the quantity of three minus three i plus the quantity of one minus
viva [34]

I think the question is simplify

\dfrac{\sqrt{-16}}{3 - 3i} + 1-2i

= \dfrac{4\sqrt{-1}}{3(1-i)}+ 1-2i

= \dfrac{4}{3}\dfrac{i}{1-i} \cdot \dfrac{1+i}{1+i} + 1-2i


= \dfrac{4}{3} \dfrac{i-1}{2} + 1-2i

= \dfrac{2}{3} i - \dfrac{2}{3} + 1-2i

= \dfrac{1}{3} - \dfrac{4}{3} i

Answer: (1/3) - (4/3)i

I might be getting the question wrong. It might be

\dfrac{\sqrt{-16}}{3 - 3i + (1-2i)}

Let's do this one too.

= \dfrac{4i}{4 - 5i} \cdot \dfrac{4+5i}{4+5i}

= \dfrac{16i - 20}{4^2 + 5^2}

=-\dfrac{20}{41} + \dfrac{16}{41} i


4 0
3 years ago
Please help and thank you
hram777 [196]

Answer:

First one

Step-by-step explanation:

The formula is y-y=m(x-x)

Since the coordinates are negatives. Double negatives make positive.

Hope that helps:)

7 0
3 years ago
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