find the zeros of the polynomial x square-3 and verify the reationship between the zeros and the coefficient.
1 answer:
Answer:
√3, and -√3
Step-by-step explanation:
to find the zeros or roots of the polinomial x²-3 make it equal to zero and solve for x
x²-3=0 add 3 to both sides to isolate x
x² = 3 squareroot both sides
√x²= √3
x= ±√3 are the two zeros
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Answer:
The statement is true because the set of rational numbers is a subset of the set of natural numbers.
Step-by-step explanation:
We just started learning this yesterday so i'm pretty sure i'm right but, I hope it helps.
Option B is correct.
Step-by-step explanation:
We need to solve: ![\sqrt[3]{x^2}\sqrt[4]{x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D)
We know that: ![\sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%5Csqrt%5Bb%5D%7Bx%7D%20%3D%5Csqrt%5Bn%2Ab%5D%7Bx.x%7D%3D%20%5Csqrt%5Bn%2Ab%5D%7Bx%5E2%7D)
Applying the above rule:
![\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D%5C%5C%3D%5Csqrt%5B3%2A4%5D%7Bx%5E2.x%5E3%7D%5C%5C%3D%5Csqrt%5B12%5D%7Bx%5E5%7D)
So, Option B is correct.
Keywords: Solving with Exponents
Learn more about Solving with Exponents at:
#learnwithBrainly
Area as a function of length can be written as
f(l) = l^2
And volume of cube can be expressed as a function of side s as,
f(s) = s^3
11 < square root of 85 because that is 9.219...
~JZ
Answer:
Step-by-step explanation:
Using the formula
Initial -final/initial =%/100
89-72/89 =%/100
17/89 =%/100
Making %subject of the formula
% =17*100/89
So % =1700/89
%= 19.101
Therefore rounding off the answer we have
X=19%
