Answer:
The pair of triangles that are congruent by the ASA criterion isΔ ABC and Δ XYZ.
The pair of triangles that are congruent by the SAS criterion is Δ BAC and ΔRQP.
Step-by-step explanation:
Two triangles are congruent by ASA property if any two angles and their included side are equal in both triangles .In triangles Δ ABC and Δ XYZ the equal side 5 is between the two equal angles. So these triangles are congruent by ASA criterion.
Two triangles are congruent by SAS if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle .In triangles Δ BAC and ΔRQP. the included angles A and Q are equal and hence the triangles are congruent by SAS criterion.
j=4.88 when g=8 and v=11
Further explanation:
When the increase/decrease in one quantity cause increase/decrease in other quantity, it is called direct variation.
Variation is always accompanied by a variation constant.
<u>Given</u>
g and v vary directly with j
IT can be written as:
j∝gv
Putting the variation constant k
j = kgv
Putting g = 6 and v=3

So the value of k is 1/18 which makes the equation

So, j=4.88 when g=8 and v=11
Keywords: Variation, Direct Variation
Learn more about variation at:
#LearnwithBrainly
Answer:
an equation of the first degree in any number of variables.
Step-by-step explanation:
Answer:
g=7.5
Step-by-step explanation:
2/3g=45
divide both sides by 2/3
g=7.5
or
g=7 1/2
Answer:
Step-by-step explanation:
The mean SAT score is
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it
) is

Next they draw a random sample of n=70 students, and they got a mean score (denoted by
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>