86.34 minutes was used to cool the soup to 80 °F
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How can we calculate this using Newton's Law of Cooling?</h3>
Newton's Law of Cooling can be computed as :
The initial temperature is been represent by T0 which is ( 100 F)
The temperature of surrounding is been given as (69 F)
The final temperature is been given as T
t = time
we were told that the temperature of the soup move to 95 F, using 15 minutes.
Hence, T = 95 F
t = 15 min
Then we can input the values into the above equation as :
if we simplify this , we have
Then 
Then we can find the value of k as :
k= -0.012
Then we have the new equation as
Then at T=80F
we have,
t=86.34
Then if we simplify , we have t=86.34 which implies that 86.34 minutes was used to cool the soup to 80 °F
Learn more about Newton's Law of Cooling at:
brainly.com/question/17051432
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Answer:
1/3
Step-by-step explanation:
A die has 6 numbers 1-6 and there are two numbers higher then 4, 5 and 6. so that is 2/6 or 1/3
Answer:
The answer would be 8.
Step-by-step explanation:
This is a percentage question, and I have struggled with these before but this is the <em>easiest</em> way to solve it given these certain criteria.
Alright, so it's given that:
A) 90%= an A grade
and
B) This is an 80-question test.
Given these, we can do the following:
90% times 80, which equals <em>72</em>.
Just to check, we know that to convert percentages to fractions, we move the decimal two spots to the left, therefore 90%= 0.90, or 0.9. We take 72 and divide it by 80, and we get 0.9, thus showing that it is correct.
Then, we do 80-72 and using simple math we get 8.
In order to find this, you will need to find the LCM of 8 and 6. This would be 24. For Bowls, 6*4 is 24 and cups 8*3 is 24.
So therefore
Bowls: 4 packs of 6
Cups: 3 packs of 8
