To find whether each solution is a solution to the ineqiality, we need to plug it into the equation.
Let's try the first one:
-6 + 3(0)>=-8
-6 + 0 >= -8
-6 >= -8
This is true, therefore this is a solution.
0 + 3(-3)>=-8
-9 >= -8
No, this is not a solution.
-5 + 3(-1) >= -8
-5 + -3 >= -8
-8 >= -8
Yes, this is a solution.
-16 + 3(-2) >= -8
-16 + -6 >= -8
-22 >= -8
No, this is not a solution.
-1 + 3(-2) >= -8
-1 + -6 >= -8
-7 >= -8
Yes, this is a solution.
Answer: a, c, and e are solutions.
Hope this helps!
Answer:
1:3
Step-by-step explanation:
First, you need to make a system of equations for the situation.
Let G represent the number of girls and B represent the number of boys.
Since there are twice as many girls as boys,
G = 2B
There are a total of 30 students in class so,
G + B = 30
or
G + B = TOTAL
In order to find the ratio of BOYS to the TOTAL STUDENTS,
you plug in B values that make up G.
(2B ) + B = TOTAL
3B = TOTAL
B = TOTAL / 3 or (1/3) TOTAL
Since B is one third of the total number of students, the ratio is 1:3.
Answer:
the answer is 50 gallons
Step-by-step explanation:
200/4 = 50
The equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S
To answer the question, we need to know what an equation is
<h3>What is an equation?</h3>
An equation is a mathematical expression that show the relationship between two variables.
Given 9cos(sin¯¹(x)) = √(81 – 81x²), we need to show L.H.S = R.H.S
So, L.H.S = 9cos(sin¯¹(x))
= 9[√{1 - sin²(sin¯¹(x)}] (Since sin²y + cos²y = 1 ⇒ cosy = √[1 - sin²y])
9[√{1 - sin²(sin¯¹(x)}] = √9² × √{1 - sin²(sin¯¹(x)}]
= √[9² × {1 - sin²(sin¯¹(x)}]
= √[81 × {1 - sin²(sin¯¹(x)}]
= √[81 × {1 - x²}] (since sin²(sin¯¹(x) = [sin(sin¯¹(x)]² = x²)
= √(81 – 81x²)
= R.H.S
So, the equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S
Learn more about equations here:
brainly.com/question/2888445
#SPJ1
