Question

A lab assistant needs to create a 600 mL mixture that is 3% hydrochloric acid. The

Answer 1

Answer:

240 ml of 1.5% solution and 360 ml of 4% solution should be used.

Step-by-step explanation:

Since a lab assistant needs to create a 600 mL mixture that is 3% hydrochloric acid, and the assistant has solutions of 1.5% and 4% in supply at the lab, to determine the number of milliliters of the 1.5% solution and the number of milliliters of the 4% solution that must be used, the following calculations must be performed:

50 x 0.015 + 50 x 0.04 = 0.75 + 2 = 2.75

40 x 0.015 + 60 x 0.04 = 0.6 + 2.4 = 3

600 x 0.4 = 240

Therefore, 240 ml of 1.5% solution and 360 ml of 4% solution should be used.