0.0338 divided by 1.3 equals 0.026
Answer:
D. Because we would be interested in any difference between running on hard and soft surfaces, we should use a two-sided hypothesis test
Step-by-step explanation:
Hello!
When planning what kind of hypothesis to use, you have to take into account any other studies that were made about that topic so that you can decide the orientation you will give them.
Normally, when there is no other information available to give an orientation to your experiment, the first step to take is to make a two-tailed test, for example, μ₁=μ₂ vs. μ₁≠μ₂, this way you can test whether there is any difference between the two stands. Only after having experimental evidence that there is any difference between the treatments is there any sense into testing which one is better than the other.
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The equation that can be used to determine the measure of ∠A is tanA = 9.4/6.7. The correct option is A. tanA=9.4/6.7
<h3>Trigonometry</h3>
From the question, we are to determine which of the given equations can be used to determine the measure of ∠A
In the diagram,
If ∠A is the included angle
Then,
Using<em> SOH CAH TOA</em>
Opposite = 9.4
Adjacent = 6.7
Thus,
tanA = 9.4/6.7
Hence, the equation that can be used to determine the measure of ∠A is tanA = 9.4/6.7. The correct option is A. tanA=9.4/6.7
Learn more on Trigonometry here: brainly.com/question/2673715
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Answer:
B is most likely the answer
Step-by-step explanation:
4 1/2 * 2= 9 so 15-9= 6
Pears weight is 6 Ibs and
4 1/2 *2 would make the most sense
So, since averages are defined as:

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.
So, using that logic, the other class can be represented as:

We can take both of these equations and multiply them by N:


So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

Simplified we would have P/N=3/8.