Which of the boxplots a b or c shows a sample that has a range 21 interquartile range 11 median 14

Can sum1 show me how to do this first question I’m confused

Tems11 [23]

It would be a Sherwin with a radius of 3 and a width of 2. Hope it helps

7 0

3 years ago

Mariela earned the following test scores in math: 95, 90, 100, 85, 80 Mr. Adams accidentally entered Mariela’s next test score a

Vesnalui [34]

Answer:

Before the error, the mean and the median were both 90.

The error added an outlier to the data set.

After the error, the mean was 75 and the median was 87.5

The mean was impacted by the error more than the median

Step-by-step explanation:

First is to put the data in order from smallest to largest

80,85,90,95,100

The mean is add up the data and divide by the number of points. The median is the middle of the data

Mean = (80+85+90+95+100)/5=450/5 = 90

Median = 90

When a 0 is added

0, 80,85,90,95,100

There is now an outlier, which is a data point far away from the others

Mean = (0+80+85+90+95+100)/6=450/6 = 75

Median = (85+90)/2 = 87.5

When the data set is even, take the two middle numbers and average them

The mean was impacted more than the median. It went from 90 to 75, where the median went from 90 to 87.5

5 0

3 years ago

Read 2 more answers

Instructions: Determine if the two triangles in

leonid [27]

The 2 triangles are congruent

4 0

3 years ago

HELPPPPP???

eimsori [14]

Answer:

b) The Pie Eating Contest would be more skewed

Step-by-step explanation:

Let's begin by drawing out a frequency distribution table for the given information:

Pie Eating Contest

Age Group (Years) Frequency

0 - 19 20

20 - 39 40

40 - 59 60

60 - 79 50

If all 20 people (aged 75 - 79) joined this event, the frequency tables changes to become:

Pie Eating Contest (2)

Age Group (Years) Frequency

0 - 19 20

20 - 39 40

40 - 59 60

60 - 79 70

Chili Cookoff

Age Group (Years) Frequency

0 - 19 30

20 - 39 50

40 - 59 40

60 - 79 10

If all 20 people (aged 75 - 79) joined this event, the frequency tables changes to become:

Chili Cookoff (2)

Age Group (Years) Frequency

0 - 19 30

20 - 39 50

40 - 59 40

60 - 79 30

The graphical representation of each event is attached as a picture

A histogram is skewed if its frequency distribution is biased to one side (either to the left or to the right). This implies that the histogram is not evenly distributed. When the histogram is cut into equal halves, the left side and the right side look unidentical.

A histogram is symmetrical if its frequency distribution is neither biased to the right or to the left. It implies that the histogram is evenly distributed across the left and the right side. When the histogram is cut into equal halves, the left side and the right side look identical.

When we consider the event in which all 20 people join the Pie Eating Contest, the histogram becomes skewed to the right.

When we consider the event in which all 20 people join the Chili Cookoff, the histogram becomes more symmetrical

We will observe that when all 20 people joined the Pie Eating Contest, the histogram becomes more skewed to the right and less symmetrical. On the other hand, if all 20 people join the Chili Cookoff, the histogram becomes more symmetrical and less skewed

Hence, the correct answer is option b) The Pie Eating Contest would be more skewed

5 0

3 years ago

?

Ann [662]

Answer:

x*(3x^2-7x-24)

Step-by-step explanation:

7 0

1 year ago